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醇脱氢酶(ADH)催化甲醛还原的动力学行为及 NADH 的部分非竞争性底物抑制作用。

The kinetics behavior of the reduction of formaldehyde catalyzed by Alcohol Dehydrogenase (ADH) and partial uncompetitive substrate inhibition by NADH.

机构信息

Department of Chemical Engineering and the Environment, Beijing Institute of Technology, 5 South Zhongguancun Street, Haidian District, Beijing, China, 100081.

出版信息

Appl Biochem Biotechnol. 2013 May;170(2):370-80. doi: 10.1007/s12010-013-0199-x. Epub 2013 Mar 27.

Abstract

Alcohol dehydrogenase (ADH) catalyzes the final step in the biosynthesis of methanol from CO2. Here, we report the steady-state kinetics for ADH, using a homogeneous enzyme preparation with formaldehyde as the substrate and nicotinamide adenine dinucleotide (NADH) as the cofactor. When changing NADH concentrations with the fixed concentrations of HCHO (more or less than NADH), kinetic studies revealed a particular zigzag phenomenon for the first time. Increasing formaldehyde concentration can weaken substrate inhibition and improve catalytic efficiency. The kinetic mechanism of ADH was analyzed using the secondary fitting method. The double reciprocal plots (1/v∼1/[HCHO] and 1/[NADH]) strongly demonstrated that the substrate inhibition by NADH was uncompetitive versus formaldehyde and partial. In the direction of formaldehyde reduction, ADH has an ordered kinetic mechanism with formaldehyde adding to enzyme first and product methanol released last. The second reactant NADH can combine with the enzyme-methanol complex and then methanol dissociates from it at a slower rate than from enzyme-methanol. The reaction velocity depends on the relative rates of the alternative pathways. The addition of NADH also accelerates the releasing of methanol. As a result, substrate inhibition and activation occurred intermittently, and the zigzag double reciprocal plot (1/v∼1/[NADH]) was obtained.

摘要

醇脱氢酶(ADH)催化甲醇从 CO2 生物合成的最后一步。在这里,我们报告 ADH 的稳态动力学,使用甲醛作为底物和烟酰胺腺嘌呤二核苷酸(NADH)作为辅助因子的均相酶制剂。当 NADH 浓度随固定浓度的 HCHO(多于或少于 NADH)变化时,首次发现了特定的之字形现象。增加甲醛浓度可以减弱底物抑制并提高催化效率。使用二次拟合方法分析 ADH 的动力学机制。双倒数图(1/v∼1/[HCHO]和 1/[NADH])强烈表明 NADH 对甲醛的底物抑制是竞争性的和部分的。在甲醛还原方向上,ADH 具有有序的动力学机制,甲醛首先加入酶,最后释放产物甲醇。第二个反应物 NADH 可以与酶-甲醇复合物结合,然后甲醇从复合物中以比从酶-甲醇复合物中慢的速率解离。反应速度取决于替代途径的相对速率。NADH 的加入也加速了甲醇的释放。结果,底物抑制和激活间歇性发生,得到之字形双倒数图(1/v∼1/[NADH])。

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