Helsinki Bioenergetics Group, Institute of Biotechnology, University of Helsinki, FI-00014, Helsinki, Finland.
Proc Natl Acad Sci U S A. 2013 Oct 15;110(42):16844-9. doi: 10.1073/pnas.1220379110. Epub 2013 Sep 30.
Complex IV in the respiratory chain of mitochondria and bacteria catalyzes reduction of molecular oxygen to water, and conserves much of the liberated free energy as an electrochemical proton gradient, which is used for the synthesis of ATP. Photochemical electron injection experiments have shown that reduction of the ferric/cupric state of the enzyme's binuclear heme a3/CuB center is coupled to proton pumping across the membrane, but only if oxidation of the reduced enzyme by O2 immediately precedes electron injection. In contrast, reduction of the binuclear center in the "as-isolated" ferric/cupric enzyme is sluggish and without linkage to proton translocation. During turnover, the binuclear center apparently shuttles via a metastable but activated ferric/cupric state (O(H)), which may decay into a more stable catalytically incompetent form (O) in the absence of electron donors. The structural basis for the difference between these two states has remained elusive, and is addressed here using computational methodology. The results support the notion that CuB[II] is either three-coordinated in the O(H) state or shares an OH(-) ligand with heme a3 in a strained μ-hydroxo structure. Relaxation to state O is initiated by hydration of the binuclear site. The redox potential of CuB is expected, and found by density functional theory calculations, to be substantially higher in the O(H) state than in state O. Our calculations also suggest that the neutral radical form of the cross-linked tyrosine in the binuclear site may be more significant in the catalytic cycle than suspected so far.
线粒体和细菌呼吸链中的复合物 IV 催化分子氧还原为水,并将大部分释放的自由能以电化学质子梯度的形式储存起来,用于 ATP 的合成。光化学电子注入实验表明,酶的双核血红素 a3/CuB 中心的铁/铜态还原与跨膜质子泵浦耦联,但前提是 O2 对还原酶的氧化必须紧随电子注入。相比之下,“分离”的双核中心的还原在铁/铜酶中是缓慢的,与质子转移没有联系。在周转过程中,双核中心显然通过亚稳态但激活的铁/铜态 (O(H)) 穿梭,在没有电子供体的情况下,该态可能会衰变为更稳定但无催化能力的形式 (O)。这两种状态之间的差异的结构基础仍然难以捉摸,本文使用计算方法对此进行了探讨。结果支持了这样一种观点,即 CuB[II] 在 O(H) 态下要么是三配位的,要么在应变的 μ-羟基金属结构中与 heme a3 共享一个 OH(-)配体。双核位点的水合作用引发了向状态 O 的弛豫。密度泛函理论计算表明,CuB 的氧化还原电位在 O(H) 态下比在 O 态下显著升高。我们的计算还表明,双核位点中交联酪氨酸的中性自由基形式在催化循环中可能比迄今为止的推测更为重要。