Davidsson Lena, Al-Ghanim Jameela, Al-Ati Tareq, Al-Hamad Nawal, Al-Mutairi Anwar, Al-Olayan Lulwa, Preston Thomas
Food and Nutrition Program, Environment and Life Sciences Research Center, Kuwait Institute for Scientific Research, P.O. Box 24885, Safat 13109, Kuwait.
The Public Authority for Food and Nutrition, Bayan 43600, Kuwait.
Int J Environ Res Public Health. 2016 Oct 13;13(10):1007. doi: 10.3390/ijerph13101007.
The aim of this pilot study was to assess body composition and total energy expenditure (TEE) in 35 obese 7-9 years old Kuwaiti children (18 girls and 17 boys). Total body water (TBW) and TEE were assessed by doubly-labeled water technique. TBW was derived from the intercept of the elimination rate of deuterium and TEE from the difference in elimination rates of O and deuterium. TBW was used to estimate fat-free mass (FFM), using hydration factors for different ages and gender. Fat mass (FM) was calculated as the difference between body weight and FFM. Body weight was not statistically different but TBW was significantly higher ( = 0.018) in boys (44.9% ± 3.3%) than girls (42.4% ± 3.0%), while girls had significantly higher estimated FM (45.2 ± 3.9 weight % versus 41.6% ± 4.3%; = 0.014). TEE was significantly higher in boys (2395 ± 349 kcal/day) compared with girls (1978 ± 169 kcal/day); = 0.001. Estimated physical activity level (PAL) was significantly higher in boys; 1.61 ± 0.167 versus 1.51 ± 0.870; = 0.034. Our results provide the first dataset of TEE in 7-9 years old obese Kuwaiti children and highlight important gender differences to be considered during the development of school based interventions targeted to combat childhood obesity.
这项初步研究的目的是评估35名7至9岁科威特肥胖儿童(18名女孩和17名男孩)的身体成分和总能量消耗(TEE)。通过双标记水技术评估总体水(TBW)和TEE。TBW由氘的消除率截距得出,TEE由氧和氘的消除率差异得出。使用不同年龄和性别的水合因子,通过TBW来估算去脂体重(FFM)。脂肪量(FM)通过体重与FFM的差值计算得出。男孩(44.9%±3.3%)的体重无统计学差异,但TBW显著高于女孩(42.4%±3.0%),差异有统计学意义(P = 0.018),而女孩的估算FM显著更高(45.2±3.9体重%对41.6%±4.3%;P = 0.014)。男孩的TEE(2395±349千卡/天)显著高于女孩(1978±169千卡/天);P = 0.001。男孩的估算身体活动水平(PAL)显著更高;1.61±0.167对1.51±0.870;P = 0.0