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从线粒体DNA变异推断系统发育:线粒体基因树与核基因树

INFERRING PHYLOGENIES FROM mtDNA VARIATION: MITOCHONDRIAL-GENE TREES VERSUS NUCLEAR-GENE TREES.

作者信息

Moore William S

机构信息

Department of Biological Sciences, Wayne State University, Detroit, Michigan, 48202.

出版信息

Evolution. 1995 Aug;49(4):718-726. doi: 10.1111/j.1558-5646.1995.tb02308.x.

Abstract

An accurately resolved gene tree may not be congruent with the species tree because of lineage sorting of ancestral polymorphisms. DNA sequences from the mitochondrially encoded genes (mtDNA) are attractive sources of characters for estimating the phylogenies of recently evolved taxa because mtDNA evolves rapidly, but its utility is limited because the mitochondrial genes are inherited as a single linkage group (haplotype) and provide only one independent estimate of the species tree. In contrast, a set of nuclear genes can be selected from distinct chromosomes, such that each gene tree provides an independent estimate of the species tree. Another aspect of the gene-tree versus species-tree problem, however, favors the use of mtDNA for inferring species trees. For a three-species segment of a phylogeny, the branching order of a gene tree will correspond to that of the species tree if coalescence of the alleles or haplotypes occurred in the internode between the first and second bifurcation. From neutral theory, it is apparent that the probability of coalescence increases as effective population size decreases. Because the mitochondrial genome is maternally inherited and effectively haploid, its effective population size is one-fourth that of a nuclear-autosomal gene. Thus, the mitochondrial-haplotype tree has a substantially higher probability of accurately tracking a short internode than does a nuclear-autosomal-gene tree. When an internode is sufficiently long that the probability that the mitochondrial-haplotype tree will be congruent with the species tree is 0.95, the probability that a nuclear-autosomalgene tree will be congruent is only 0.62. If each of k independently sampled nuclear-gene trees has a probability of congruence with the species tree of 0.62, then a sample of 16 such trees would be required to be as confident of the inference based on the mitochondrial-haplotype tree. A survey of mtDNA-haplotype diversity in 34 species of birds indicates that coalescence is generally very recent, which suggests that coalescence times are typically much shorter than internodal branch lengths of the species tree, and that sorting of mtDNA lineages is not likely to confound the species tree. Hybridization resulting in transfer of mtDNA haplotypes among branches could also result in a haplotype tree that is incongruent with the species tree; if undetected, this could confound the species tree. However, hybridization is usually easy to detect and should be incorporated in the historical narrative of the group, because reticulation, as well as cladistic events, contributed to the evolution of the group.

摘要

由于祖先多态性的谱系分选,精确解析的基因树可能与物种树不一致。来自线粒体编码基因(mtDNA)的DNA序列是估计最近进化类群系统发育的有吸引力的特征来源,因为mtDNA进化迅速,但其效用有限,因为线粒体基因作为一个单连锁群(单倍型)遗传,并且仅提供对物种树的一个独立估计。相比之下,可以从不同染色体中选择一组核基因,使得每个基因树都提供对物种树的独立估计。然而,基因树与物种树问题的另一个方面有利于使用mtDNA来推断物种树。对于系统发育的一个三物种片段,如果等位基因或单倍型的合并发生在第一个和第二个分支点之间的节间,则基因树的分支顺序将与物种树的分支顺序相对应。从中性理论来看,很明显合并的概率随着有效种群大小的减小而增加。由于线粒体基因组是母系遗传且实际上是单倍体,其有效种群大小是核常染色体基因的四分之一。因此,线粒体单倍型树比核常染色体基因树更有可能准确追踪短节间。当一个节间足够长以至于线粒体单倍型树与物种树一致的概率为0.95时,核常染色体基因树一致的概率仅为0.62。如果k个独立采样的核基因树中的每一个与物种树一致的概率为0.62,那么需要16个这样的树的样本才能像基于线粒体单倍型树的推断那样有信心。对34种鸟类的mtDNA单倍型多样性的调查表明,合并通常非常近,这表明合并时间通常比物种树的节间分支长度短得多,并且mtDNA谱系的分选不太可能混淆物种树。杂交导致mtDNA单倍型在分支之间转移也可能导致单倍型树与物种树不一致;如果未被检测到,这可能会混淆物种树。然而,杂交通常很容易检测到,并且应该纳入该类群的历史叙述中,因为网状进化以及分支进化事件都对该类群的进化有贡献。

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