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复杂疾病核心家系中连锁与遗传异质性的检测:单标记位点与双标记位点比较

The detection of linkage and heterogeneity in nuclear families for complex disorders: one versus two marker loci.

作者信息

Martinez M M, Goldin L R

机构信息

Clinical Neurogenetics Branch, National Institutes of Health, Bethesda, MD 20892.

出版信息

Am J Hum Genet. 1989 Apr;44(4):552-9.

Abstract

Using exact expected likelihoods, we have computed the average number of phase-unknown nuclear families needed to detect linkage and heterogeneity. We have examined the case of both dominant and recessive inheritance with reduced penetrance and phenocopies. Most of our calculations have been carried out under the assumption that 50% of families are linked to a marker locus. We have varied both the number of offspring per family and the sampling scheme. We have also investigated the increased power when the disease locus is midway between two marker loci 10 cM apart. For recessive inheritance, both linkage and heterogeneity can be detected in clinically feasible sample sizes. For dominant inheritance, linkage can be detected but heterogeneity cannot be detected unless larger sibships (four offspring) are sampled or two linked markers are available. As expected, if penetrance is reduced, sampling families with all sibs affected is most efficient. Our results provide a basis for estimating the amount of resources needed to find genes for complex disorders under conditions of heterogeneity.

摘要

使用精确的期望似然性,我们计算了检测连锁和遗传异质性所需的未知相位核心家庭的平均数量。我们研究了显性和隐性遗传且具有降低的外显率和表型模拟的情况。我们的大多数计算是在50%的家庭与一个标记位点连锁的假设下进行的。我们改变了每个家庭的后代数量和抽样方案。我们还研究了疾病位点位于相距10厘摩的两个标记位点中间时检测力的提高情况。对于隐性遗传,在临床可行的样本量下可以检测到连锁和遗传异质性。对于显性遗传,可以检测到连锁,但除非抽样更大的同胞组(四个后代)或有两个连锁标记,否则无法检测到遗传异质性。正如预期的那样,如果外显率降低,对所有受影响同胞的家庭进行抽样是最有效的。我们的结果为估计在遗传异质性条件下寻找复杂疾病基因所需的资源量提供了基础。

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