Al-Nasser I, Crompton M
Biochem J. 1986 Oct 1;239(1):19-29. doi: 10.1042/bj2390019.
Rat liver mitochondria became permeabilized to sucrose according to an apparent first-order process after accumulating 35 nmol of Ca2+/mg of protein in the presence of 2.5 mM-Pi, but not in its absence. A fraction (24-32%) of the internal space remains sucrose-inaccessible. The rate constant for permeabilization to sucrose decreases slightly when the pH is decreased from 7.5 to 6.5, whereas the rate of inner-membrane potential (delta psi) dissipation is markedly increased, which indicates that H+ permeation precedes sucrose permeation. Permeabilization does not release mitochondrial proteins. [14C]Sucrose appears to enter permeabilized mitochondria instantaneously. Chelation of Ca2+ with EGTA restores delta psi and entraps sucrose in the matrix space. With 20 mM-sucrose at the instant of resealing, about 21 nmol of sucrose/mg of protein becomes entrapped. The amount of sucrose entrapped is proportional to the degree of permeabilization. Entrapped sucrose is not removed by dilution of the mitochondrial suspension. Resealed mitochondria washed three times retain about 74% of the entrapped sucrose. In the presence of Ruthenium Red and Ca2+ buffers permeabilized mitochondria reseal only partially with free [Ca2+] greater than 3 microM. [14C]Sucrose enters partially resealed mitochondria continuously with time, despite maintenance of delta psi, in accordance with continued interconversion of permeable and impermeable forms. Kinetic analyses of [14C]sucrose entry indicate two Ca2+-sensitive reactions in permeabilization. This conclusion is supported by the biphasic time courses of resealing and repolarization of permeabilized mitochondria and the acute dependence of the rapid repolarization on the free [Ca2+]. A hypothetical model of permeabilization and resealing is suggested and the potential of the procedure for matrix entrapment of substances is discussed.
在2.5 mM无机磷酸盐存在的情况下,当大鼠肝脏线粒体积累35 nmol Ca²⁺/mg蛋白质时,会按照明显的一级过程对蔗糖变得通透,而在无无机磷酸盐时则不会。内部空间的一部分(24 - 32%)对蔗糖仍然不可通透。当pH从7.5降至6.5时,对蔗糖通透的速率常数略有下降,而内膜电位(Δψ)耗散的速率则显著增加,这表明H⁺渗透先于蔗糖渗透。通透不会释放线粒体蛋白质。[¹⁴C]蔗糖似乎能瞬间进入通透的线粒体。用乙二醇双四乙酸(EGTA)螯合Ca²⁺可恢复Δψ并将蔗糖截留在基质空间中。在重新封闭瞬间加入20 mM蔗糖时,约21 nmol蔗糖/mg蛋白质会被截留。截留的蔗糖量与通透程度成正比。截留的蔗糖不会因线粒体悬浮液的稀释而被去除。洗涤三次后的重新封闭的线粒体保留了约74%截留的蔗糖。在钌红和Ca²⁺缓冲液存在的情况下,当游离[Ca²⁺]大于3 μM时,通透的线粒体只能部分重新封闭。尽管维持着Δψ,但[¹⁴C]蔗糖会随着时间持续进入部分重新封闭的线粒体,这与可通透和不可通透形式的持续相互转化一致。对[¹⁴C]蔗糖进入的动力学分析表明,通透过程中有两个对Ca²⁺敏感的反应。通透的线粒体重新封闭和复极化的双相时间进程以及快速复极化对游离[Ca²⁺]的急性依赖性支持了这一结论。本文提出了一个通透和重新封闭的假设模型,并讨论了该方法用于基质截留物质的潜力。