一种苯乙烯基苯并噻唑铂（II）配合物的结构：[四乙基铵][三溴化铂（苯乙烯基苯并噻唑）]
Structure of a styrylbenzothiazole platinum(II) complex: [NEt4][PtBr3(asb)].
作者信息
Gomez G M, Muir M M, Muir J A, Cox O
机构信息
Deparment of Chemistry, University of Puerto Rico, Rio Piedras.
出版信息
Acta Crystallogr C. 1988 Sep 15;44 ( Pt 9):1554-7. doi: 10.1107/s010827018800558x.
Tetraethylammonium tribromo[2-(2- acetoxystyryl)benzothiazole]platinate(II), [(C2H5)4N]-[PtBr3(C17H13NO2S)], Mr = 860.4 monoclinic, P21/c, a = 11.230 (9), b = 19.333 (4), c = 13.685 (6) A, beta = 101.06 (4) degrees, V = 2916 (4) A3, Z = 4, D chi = 1.96 g cm-3, lambda(Mo K alpha) = 0.71073 A, mu = 90.3 cm-1, F(000) = 1648, T = 296 K, final R = 0.047 for 3384 unique observed reflections. The [PtBr3(asb)]- unit has square-planar geometry about the Pt, with the asb coordinated to the Pt through the N of the thiazole ring and a Pt-N bond distance of 2.010 (8) A. The average Pt-Br distance is 2.426 (7) A. The ligand is non-planar with a dihedral angle of 22.4 (7) degrees between the benzothiazole and the acetoxybenzene rings. The dihedral angles between the platinum coordination plane and the benzothiazole and benzene rings are 85.7 (1) and 71.3 (3) degrees respectively.
三溴化[2-(2-乙酰氧基苯乙烯基)苯并噻唑]四乙铵合铂(II)，[(C₂H₅)₄N]-[PtBr₃(C₁₇H₁₃NO₂S)]，Mr = 860.4，单斜晶系，P2₁/c，a = 11.230 (9)，b = 19.333 (4)，c = 13.685 (6) Å，β = 101.06 (4)°，V = 2916 (4) ų，Z = 4，Dχ = 1.96 g cm⁻³，λ(Mo Kα) = 0.71073 Å，μ = 90.3 cm⁻¹，F(000) = 1648，T = 296 K，对于3384个独特的观测反射，最终R = 0.047。[PtBr₃(asb)]⁻单元中Pt周围具有平面正方形几何结构，asb通过噻唑环的N与Pt配位，Pt-N键长为2.010 (8) Å。Pt-Br的平均键长为2.426 (7) Å。配体是非平面的，苯并噻唑环与乙酰氧基苯环之间的二面角为22.4 (7)°。铂配位平面与苯并噻唑环和苯环之间的二面角分别为85.7 (1)°和71.3 (3)°。
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