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核黄素的生物合成。由戊糖磷酸通过酶促反应形成6,7-二甲基-8-核糖基芦竹碱。

Biosynthesis of riboflavin. Enzymatic formation of 6,7-dimethyl-8-ribityllumazine from pentose phosphates.

作者信息

Nielsen P, Neuberger G, Fujii I, Bown D H, Keller P J, Floss H G, Bacher A

出版信息

J Biol Chem. 1986 Mar 15;261(8):3661-9.

PMID:3949782
Abstract

The xylene ring of riboflavin originates by dismutation of the precursor, 6,7-dimethyl-8-ribityllumazine. The formation of the latter compound requires a 4-carbon unit as the precursor of carbon atoms 6 alpha, 6, 7, and 7 alpha of the pyrazine ring. The formation of riboflavin from GTP and ribose phosphate by cell extract from Candida guilliermondii has been observed by Logvinenko et al. (Logvinenko, E. M., Shavlovsky, G. M., Zakal'sky, A. E., and Zakhodylo, I. V. (1982) Biokhimiya 47, 931-936). We have studied this enzyme reaction in closer detail using carbohydrate phosphates as substrates and synthetic 5-amino-6-ribitylamino-2,4-(1H,3H)-pyrimidinedione or its 5'-phosphate as cosubstrates. Several pentose phosphates and pentulose phosphates can serve as substrate for the formation of riboflavin with similar efficiency. The reaction requires Mg2+. Various samples of ribulose phosphate labeled with 14C or 13C have been prepared and used as enzyme substrates. Radioactivity was efficiently incorporated into riboflavin from [1-14C]ribulose phosphate, [3,5-14C]ribulose phosphate, and [5-14C]ribulose phosphate, but not from [4-14C]ribulose phosphate. Label from [1-13C]ribose 5-phosphate was incorporated into C6 and C8 alpha of riboflavin. [2,3,5-13C]Ribose 5-phosphate yielded riboflavin containing two contiguously labeled segments of three carbon atoms, namely 5a, 9a, 9 and 8, 7, 7 alpha. 5-Amino-6-[1'-14C] ribitylamino-2,4 (1H,3H)-pyrimidinedione transferred radioactivity exclusively to the ribityl side chain of riboflavin in the enzymatic reaction. It follows that the 4-carbon unit used for the biosynthesis of 6,7-dimethyl-8-ribityllumazine consists of the pentose carbon atoms 1, 2, 3, and 5 in agreement with earlier in vivo studies.

摘要

核黄素的二甲苯环由前体6,7-二甲基-8-核糖基卢马嗪的歧化反应产生。后一种化合物的形成需要一个4碳单元作为吡嗪环碳原子6α、6、7和7α的前体。Logvinenko等人(Logvinenko, E. M., Shavlovsky, G. M., Zakal'sky, A. E., and Zakhodylo, I. V. (1982) Biokhimiya 47, 931 - 936)观察到季也蒙假丝酵母的细胞提取物能将鸟苷三磷酸(GTP)和磷酸核糖转化为核黄素。我们使用碳水化合物磷酸盐作为底物,以合成的5-氨基-6-核糖基氨基-2,4-(1H,3H)-嘧啶二酮或其5'-磷酸盐作为共底物,对该酶反应进行了更详细的研究。几种戊糖磷酸酯和戊酮糖磷酸酯都可以作为合成核黄素效率相近的底物。该反应需要Mg2 +。已经制备了用14C或13C标记的各种磷酸核酮糖样品并用作酶底物。放射性有效地从[1-14C]磷酸核酮糖、[3,5-14C]磷酸核酮糖和[五-14C]磷酸核酮糖掺入到核黄素中,但未从[4-14C]磷酸核酮糖掺入。[1-13C]核糖5-磷酸的标记掺入到核黄素的C6和C8α中。[2,3,5-13C]核糖5-磷酸产生的核黄素含有两个三个碳原子连续标记的片段,即5a、9a、9和八、七、7α。5-氨基-6-[1'-14C]核糖基氨基-2,4(1H,3H)-嘧啶二酮在酶促反应中将放射性仅转移到核黄素的核糖基侧链上。由此可见,用于生物合成6,7-二甲基-8-核糖基卢马嗪的4碳单元由戊糖碳原子1、2、3和5组成,这与早期的体内研究结果一致。

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