Department of Applied Mathematics and Theoretical Physics, University of Cambridge, Cambridge CB3 0WA, UK.
J R Soc Interface. 2024 Nov;21(220):20240283. doi: 10.1098/rsif.2024.0283. Epub 2024 Nov 6.
Numerous studies have explored the link between bacterial swimming and the number of flagella, a distinguishing feature of motile multi-flagellated bacteria. We revisit this open question using augmented slender-body theory simulations, in which we resolve the full hydrodynamic interactions within a bundle of helical filaments rotating and translating in synchrony. Unlike previous studies, our model considers the full torque-speed relationship of the bacterial flagellar motor, revealing its significant impact on multi-flagellated swimming. Because the viscous load per motor decreases with the flagellar number, the bacterial flagellar motor transitions from the high-load to the low-load regime at a critical number of filaments, leading to bacterial slowdown as further flagella are added to the bundle. We explain the physical mechanism behind the observed slowdown as an interplay between the load-dependent generation of torque by the motor, and the load-reducing cooperativity between flagella, which consists of both hydrodynamic and non-hydrodynamic components. The theoretically predicted critical number of flagella is remarkably close to the values reported for the model organism . Our model further predicts that the critical number of flagella increases with viscosity, suggesting that bacteria can enhance their swimming capacity by growing more flagella in more viscous environments, consistent with empirical observations.
许多研究都探讨了细菌游动与鞭毛数量之间的关系,鞭毛是运动多鞭毛细菌的一个显著特征。我们使用增强的细长体理论模拟重新研究了这个悬而未决的问题,在该模拟中,我们在同步旋转和移动的螺旋丝束内解析了全部分离的流体动力相互作用。与之前的研究不同,我们的模型考虑了细菌鞭毛马达的完整扭矩-速度关系,揭示了其对多鞭毛游动的显著影响。由于每个马达的粘性负载随鞭毛数量的减少而减少,因此当鞭毛数量达到临界值时,细菌鞭毛马达会从高负载状态转变为低负载状态,导致细菌在添加更多鞭毛时速度减缓。我们将观察到的减速现象背后的物理机制解释为马达产生的扭矩与鞭毛之间的负载相关的协同作用之间的相互作用,这种协同作用既包括流体动力成分,也包括非流体动力成分。理论预测的临界鞭毛数量与模型生物的报告值非常接近。我们的模型进一步预测,临界鞭毛数量随粘度的增加而增加,这表明细菌可以通过在更粘稠的环境中生长更多的鞭毛来提高游动能力,这与经验观察一致。