Koch A L
Genetics. 1972 Oct;72(2):297-316. doi: 10.1093/genetics/72.2.297.
The proportion of two allelic mutant forms of a haploid species can be calculated from six quantities, the original proportion, the two effective growth rate constants, the two mutation rate constants for the transition from one to the other, and the elapsed time. With a program for carrying out this calculation in a mini-computer, we set about investigating the rates of exploration of multiple intragene changes in populations of enormous numbers over a large number of cell generations. It seemed evident from the outset that unless in the past very different proportions of the different types of mutational changes occurred, then neither the numbers nor the times could have been of sufficient magnitude to account for enzyme evolution by multiple simultaneous changes within a gene to yield a superior protein. Rather, we propose that the more rapid path of enzyme evolution consisted of the sequence: 1) gene duplication, 2) inactivation of a gene copy by a chain-terminating mutation or other mutational change which suppresses transcription and/or translation, 3) multiple base-pair changes and/or small deletions and additions within the non-functioning gene, and finally, 4) reversion of the mutation which was suppressing translation. It is shown that this path will lead to faster advance, if the selective advantages of different forms are dependent on the function of the gene products at certain times in history, while at other times, although this function may be necessary, it is not limiting for growth.
单倍体物种的两种等位基因突变形式的比例可以根据六个量来计算,即原始比例、两个有效生长速率常数、从一种形式转变为另一种形式的两个突变率常数以及经过的时间。利用一个在小型计算机上进行此项计算的程序,我们着手研究在大量细胞世代中数量庞大的群体内多个基因内变化的探索速率。从一开始就似乎很明显,除非在过去不同类型的突变变化发生的比例有很大差异,否则无论是数量还是时间都不足以解释通过基因内多个同时发生的变化来产生一种更优蛋白质从而实现酶的进化。相反,我们提出酶进化的更快途径包括以下序列:1)基因复制,2)通过链终止突变或其他抑制转录和/或翻译的突变变化使一个基因拷贝失活,3)在无功能基因内发生多个碱基对变化和/或小的缺失和插入,最后,4)抑制翻译的突变的回复突变。结果表明,如果不同形式的选择优势在历史上的某些时期取决于基因产物的功能,而在其他时期,尽管这种功能可能是必要的,但对生长没有限制,那么这条途径将导致更快的进展。