编码延伸因子G的大肠杆菌fus基因的核苷酸序列。
The nucleotide sequence of the Escherichia coli fus gene, coding for elongation factor G.
作者信息
Zengel J M, Archer R H, Lindahl L
出版信息
Nucleic Acids Res. 1984 Feb 24;12(4):2181-92. doi: 10.1093/nar/12.4.2181.
Abstract
We have determined the nucleotide sequence of the Escherichia coli fus gene, which codes for elongation factor G. The protein product of the sequenced gene contains 703 amino acids, with a predicted molecular weight of 77,444. The fus gene shows the nonrandom pattern of codon usage typical of ribosomal proteins and other proteins synthesized at a high level. We have identified several potential promoter sequences within the gene. One of these sequences may correspond to the secondary promoter for expression of the downstream tufA gene (encoding elongation factor Tu) whose activity has been described previously (1,2). A comparison of the nucleotide and amino acid sequences of elongation factors G and Tu reveals a limited but significant homology between the two proteins within the 150 amino acid residues at their amino-terminal ends.
摘要
我们已经确定了大肠杆菌fus基因的核苷酸序列，该基因编码延伸因子G。测序基因的蛋白质产物包含703个氨基酸，预测分子量为77444。fus基因显示出核糖体蛋白和其他高水平合成的蛋白质典型的非随机密码子使用模式。我们在该基因内鉴定出了几个潜在的启动子序列。其中一个序列可能对应于下游tufA基因（编码延伸因子Tu）表达的次要启动子，其活性先前已有描述(1,2)。延伸因子G和Tu的核苷酸及氨基酸序列比较显示，这两种蛋白质在其氨基末端的150个氨基酸残基范围内存在有限但显著的同源性。
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