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电离辐射和氚嬗变都会导致细胞DNA中形成5-羟甲基-2'-脱氧尿苷。

Ionizing radiation and tritium transmutation both cause formation of 5-hydroxymethyl-2'-deoxyuridine in cellular DNA.

作者信息

Teebor G W, Frenkel K, Goldstein M S

出版信息

Proc Natl Acad Sci U S A. 1984 Jan;81(2):318-21. doi: 10.1073/pnas.81.2.318.

Abstract

HeLa cells grown in the presence of [methyl-3H]thymidine contained large amounts of 5-hydroxymethyl-2'-deoxyuridine (HMdU) in their DNA. When the cells were grown in [6-3H]thymidine and their DNA was labeled to the same specific activity, no HMdU was present. When such [6-3H]thymidine-labeled cells were exposed to increasing amounts of gamma-radiation, small but increasing amounts of HMdU were formed in their DNA. This indicates that HMdU can be formed in DNA by two distinct mechanisms. The first is the result of the transmutation of 3H to 3He (beta decay) in the methyl group of thymidine, leading to formation of a carbocation. This short-lived ion reacts with hydroxide ions of water, yielding the hydroxymethyl group. HMdU that is formed by this mechanism is formed at the rate of beta decay of 3H. It appears only in [methyl-3H]thymidine residues and is present in the DNA of both nonirradiated and gamma-irradiated cells. The second mechanism is the result of the radiolysis of water caused by ionizing radiation. The resultant radical species, particularly hydroxyl radicals, may react with many sites on DNA. When the methyl group of thymine is attacked by hydroxyl radicals, the hydroxymethyl group is formed. The formation of HMdU by this mechanism was detected only when [6-3H]thymidine-labeled cells were used, since transmutation of 3H in position 6 of thymine cannot yield HMdU.

摘要

在含有[甲基 - ³H]胸苷的条件下培养的HeLa细胞,其DNA中含有大量的5 - 羟甲基 - 2'-脱氧尿苷(HMdU)。当细胞在[6 - ³H]胸苷中培养且其DNA被标记至相同的比活度时,未检测到HMdU。当这种用[6 - ³H]胸苷标记的细胞暴露于剂量不断增加的γ辐射时,其DNA中会形成少量但不断增加的HMdU。这表明HMdU可通过两种不同机制在DNA中形成。第一种机制是胸苷甲基中的³H嬗变为³He(β衰变)的结果,导致形成碳正离子。这种短寿命离子与水的氢氧根离子反应,生成羟甲基。通过这种机制形成的HMdU以³H的β衰变速率形成。它仅出现在[甲基 - ³H]胸苷残基中,且存在于未受辐射和γ辐射细胞的DNA中。第二种机制是电离辐射引起的水的辐射分解的结果。产生的自由基物种,特别是羟基自由基,可能与DNA上的许多位点发生反应。当胸腺嘧啶的甲基受到羟基自由基攻击时,就会形成羟甲基。仅在用[6 - ³H]胸苷标记的细胞中才能检测到通过这种机制形成的HMdU,因为胸腺嘧啶6位上的³H嬗变不会产生HMdU。

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