Kobayashi I, Hosaka K, Ueno T, Maruo H, Kamiyama M, Konno C, Gemba M
Toxicological Research Center, Nitto Denko Corporation, Osaka, Japan.
Biol Pharm Bull. 1996 Jun;19(6):839-44. doi: 10.1248/bpb.19.839.
In the present study we evaluated the relationship between the cumulative amount of propranolol permeating through the stratum corneum and the formation of erythema, a skin irritation reaction, after transdermal application of adhesive patches containing propranolol to the skin of guinea pigs. The intensity of erythema was expressed in terms of a* values measured with a chromameter. The a* values increased in guinea pigs after application of the adhesive patches containing 0.4 mg/cm2 of propranolol to the skin. Since the adhesive patches showed good adhesion to the skin (propranolol content is less than the saturated concentration in the adhesive base) and the cumulative amount of propranolol permeating through the stratum corneum is small, the development of erythema was considered to be mainly due to physical factors such as peeling. Even in adhesive patches containing 0.8 mg/cm2 or 1.2 mg/cm2 of propranolol, a* values increased, although adhesion to the skin is low because of crystallization of propranolol in the adhesive base. On the other hand, in these two adhesive patches, the cumulative amount of propranolol permeating through the stratum corneum increased up to 24 h after application. These findings suggest that the skin irritation reaction is due to propranolol mainly absorbed transdermally, because there is a high correlation between the cumulative amount of propranolol permeating through the stratum corneum and the a* values (r = 0.928).
在本研究中,我们评估了普萘洛尔透过角质层的累积量与红斑形成之间的关系,红斑是一种皮肤刺激反应,在将含普萘洛尔的粘贴片经皮应用于豚鼠皮肤后进行观察。红斑强度用色度计测量的a值表示。在向豚鼠皮肤应用含0.4mg/cm²普萘洛尔的粘贴片后,a值升高。由于粘贴片对皮肤显示出良好的粘附性(普萘洛尔含量低于粘合剂基质中的饱和浓度)且普萘洛尔透过角质层的累积量较小,因此红斑的出现被认为主要是由于诸如剥离等物理因素。即使在含0.8mg/cm²或1.2mg/cm²普萘洛尔的粘贴片中,a值也会升高,尽管由于普萘洛尔在粘合剂基质中结晶,其对皮肤的粘附性较低。另一方面,在这两种粘贴片中,普萘洛尔透过角质层的累积量在应用后24小时内增加。这些发现表明,皮肤刺激反应是由于主要经皮吸收的普萘洛尔所致,因为普萘洛尔透过角质层的累积量与a值之间存在高度相关性(r = 0.928)。