Derat Etienne, Kumar Devesh, Hirao Hajime, Shaik Sason
Department of Organic Chemistry, The Hebrew University of Jerusalem, Israel.
J Am Chem Soc. 2006 Jan 18;128(2):473-84. doi: 10.1021/ja056328f.
Density functional calculations were performed in response to the controversies regarding the identity of the oxidant species in cytochrome P450. The calculations were used to gauge the relative C-H hydroxylation reactivity of three potential oxidant species of the enzyme, the high-valent oxo-iron species Compound I (Cpd I), the ferric hydroperoxide Compound 0 (Cpd 0), and the ferric-hydrogen peroxide complex Fe(H(2)O(2)). The results for the hydroxylation of a radical probe substrate, 1, show the following trends: (a) Cpd I is the most reactive species; in its presence the other two reagents will be silent. (b) In the absence of Cpd I, substrate oxidation by Cpd 0 and Fe(H(2)O(2)) will take place via a stepwise mechanism that involves initial O-O homolysis followed by H-abstraction from 1. (c) Cpd 0 will undergo mostly porphyrin hydroxylation and only approximately 15% of substrate oxidation producing mostly the rearranged alcohol, 3 (Scheme 2). (d) Fe(H(2)O(2)) will generate mostly free hydrogen peroxide (uncoupling). A small fraction will perform substrate oxidation and lead mostly to 3. Reactivity probes for these reagents are kinetic isotope effect (KIE) and the product ratio of unrearranged to rearranged alcohols, [2/3]. Thus, for substrate oxidation by Cpd 0 or Fe(H(2)O(2)) KIE will be small, approximately 2, while Cpd I will have large KIE values. Typically both Cpd 0 and Fe(H(2)O(2)) will lead to a [2/3] ratio < 1, while Cpd I will lead to ratios > 1. In addition, the product isotope effect (KIE(2)/KIE(3) not equal 1) is expected from the reactivity of Cpd I.
针对细胞色素P450中氧化剂种类的身份存在的争议,进行了密度泛函计算。这些计算用于评估该酶的三种潜在氧化剂种类,即高价氧合铁物种化合物I(Cpd I)、氢过氧化物铁化合物0(Cpd 0)和铁-过氧化氢复合物Fe(H₂O₂)的相对C-H羟基化反应活性。自由基探针底物1的羟基化结果显示出以下趋势:(a)Cpd I是反应活性最高的物种;在其存在下,其他两种试剂将不发生反应。(b)在没有Cpd I的情况下,Cpd 0和Fe(H₂O₂)对底物的氧化将通过逐步机制进行,该机制涉及初始的O-O均裂,随后从1中夺取氢。(c)Cpd 0主要进行卟啉羟基化,只有大约15%的底物氧化主要生成重排醇3(方案2)。(d)Fe(H₂O₂)主要产生游离过氧化氢(解偶联)。一小部分将进行底物氧化,主要生成3。这些试剂的反应活性探针是动力学同位素效应(KIE)和未重排醇与重排醇的产物比率[2/3]。因此,对于Cpd 0或Fe(H₂O₂)对底物的氧化,KIE将很小,约为2,而Cpd I将具有较大的KIE值。通常,Cpd 0和Fe(H₂O₂)都会导致[2/3]比率<1,而Cpd I会导致比率>1。此外,根据Cpd I的反应活性,预计会有产物同位素效应(KIE₂/KIE₃≠1)。