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变形链球菌中5-磷酸木糖醇的排出机制。

Expulsion mechanism of xylitol 5-phosphate in Streptococcus mutans.

作者信息

Pihlanto-Leppälä A, Söderling E, Mäkinen K K

机构信息

Department of Biochemistry, University of Turku, Finland.

出版信息

Scand J Dent Res. 1990 Apr;98(2):112-9. doi: 10.1111/j.1600-0722.1990.tb00949.x.

Abstract

The expulsion mechanism of xylitol 5-phosphate in Streptococcus mutans ATCC 25175 was studied using resting cells incubated in the presence of 14C-xylitol. The expulsion appeared to be a two-step process: xylitol 5-phosphate was first hydrolyzed to xylitol and inorganic phosphate, and the xylitol was subsequently expelled from the cells. The dephosphorylation step appeared to be energy-requiring and it was most likely associated with a phosphatase which was active on xylitol 5-phosphate. Two to three successive cultivations of the cells in the presence of 6% xylitol increased this enzyme activity 4.3-fold. These results are in accordance with the presence of an energy-dependent xylitol 5-phosphate cycle in S. mutans, which is regulated by exogenous xylitol.

摘要

利用在含14C-木糖醇的条件下孵育的静息细胞,研究了变形链球菌ATCC 25175中5-磷酸木糖醇的排出机制。排出似乎是一个两步过程:5-磷酸木糖醇首先水解为木糖醇和无机磷酸,随后木糖醇从细胞中排出。去磷酸化步骤似乎需要能量,并且很可能与一种对5-磷酸木糖醇有活性的磷酸酶有关。在6%木糖醇存在的条件下对细胞进行两到三次连续培养,可使该酶活性提高4.3倍。这些结果与变形链球菌中存在受外源木糖醇调节的能量依赖性5-磷酸木糖醇循环一致。

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