Fun Hoong-Kun, Quah Ching Kheng, Shyma P C, Kalluraya Balakrishna, Vidyashree J H S
Acta Crystallogr Sect E Struct Rep Online. 2012 Jul 1;68(Pt 7):o2122. doi: 10.1107/S1600536812026736. Epub 2012 Jun 16.
The title compound, C(14)H(11)ClFN(3)O·H(2)O, exists in an E conformation with respect to the N=C bond. The pyridine ring forms a dihedral angle of 5.00 (9)° with the benzene ring. In the crystal, the ketone O atom accepts one O-H⋯O and one C-H⋯O hydrogen bond, the water O atom accepts one N-H⋯O and two C-H⋯O hydrogen bonds and the pyridine N atom accepts one O-H⋯N hydrogen bond, forming layers parallel to the ab plane.
标题化合物C(14)H(11)ClFN(3)O·H(2)O中,N=C键呈E构型。吡啶环与苯环形成的二面角为5.00 (9)°。在晶体中,酮O原子接受一个O—H⋯O和一个C—H⋯O氢键,水O原子接受一个N—H⋯O和两个C—H⋯O氢键,吡啶N原子接受一个O—H⋯N氢键,形成平行于ab平面的层状结构。