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(E)-4-甲氧基-N'-(2,4,5-三甲氧基亚苄基)苯甲酰肼半水合物

(E)-4-Meth-oxy-N'-(2,4,5-tri-meth-oxy-benzyl-idene)benzohydrazide hemihydrate.

作者信息

Chantrapromma Suchada, Boonnak Nawong, Horkaew Jirapa, Quah Ching Kheng, Fun Hoong-Kun

机构信息

Department of Chemistry, Faculty of Science, Prince of Songkla University, Hat-Yai, Songkhla 90112, Thailand.

Faculty of Traditional Thai Medicine, Prince of Songkla University, Hat-Yai, Songkhla 90112, Thailand.

出版信息

Acta Crystallogr Sect E Struct Rep Online. 2014 Jan 15;70(Pt 2):o150-1. doi: 10.1107/S1600536814000531. eCollection 2014 Feb 1.

Abstract

The title compound crystallizes as a hemihydrate, C18H20N2O5·0.5H2O. The mol-ecule exists in an E conformation with respect to the C=N imine bond. The 4-meth-oxy-phenyl unit is disordered over two sets of sites with a refined occupancy ratio of 0.54 (2):0.46 (2). The dihedral angles between the benzene rings are 29.20 (9) and 26.59 (9)°, respectively, for the major and minor components of the 4-meth-oxy-substituted ring. All meth-oxy substituents lie close to the plane of the attached benzene rings [the Cmeth-yl-O-C-C torsion angles range from -4.0 (12) to 3.9 (2)°]. In the crystal, the components are linked into chains propagating along [001] via N-H⋯O and O-H⋯O hydrogen bonds and weak C-H⋯O inter-actions.

摘要

标题化合物以半水合物C18H20N2O5·0.5H2O的形式结晶。相对于C=N亚胺键,分子呈E构象。4-甲氧基苯基单元在两组位置上无序,精制占有率比为0.54 (2):0.46 (2)。对于4-甲氧基取代环的主要和次要组分,苯环之间的二面角分别为29.20 (9)°和26.59 (9)°。所有甲氧基取代基都靠近相连苯环的平面[C甲基-O-C-C扭转角范围为-4.0 (12)°至3.9 (2)°]。在晶体中,各组分通过N-H⋯O和O-H⋯O氢键以及弱C-H⋯O相互作用连接成沿[001]方向延伸的链。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/3ddd/3998312/20509af0da8e/e-70-0o150-fig1.jpg

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