Experimental Laboratory of Hepatology and Gastroenterology, Hospital de Clínicas de Porto Alegre (HCPA), Porto Alegre, Brazil.
Post Graduate Program in Gastroenterology and Hepatology, Universidade Federal do Rio Grande do Sul (UFRGS), Porto Alegre, Brazil.
J Am Coll Nutr. 2020 Feb;39(2):163-170. doi: 10.1080/07315724.2019.1627955. Epub 2019 Jun 26.
Alcoholic liver disease (ALD) is among the leading causes of death from liver disease. Among the factors involved in its pathogenesis are inflammation and increased intestinal permeability. The aim of this study was to assess the effect of GG (LGG) on hepatic lipid accumulation, activation of inflammasomes, and gut permeability markers in experimental model of ALD with zebrafish. An experiment was conducted to assess the effective LGG dose capable of promoting intestinal colonization. Animals were divided into three groups ( = 64/group): ethanol group (E), ethanol + probiotic group (EP), and control group (C). Groups E and EP were exposed to 0.5% ethanol concentration for 28 days. At the end of this period, animals were euthanized, and livers were collected for Oil Red staining and assessment of the inflammasome system. Intestines were collected for evaluation of gut permeability markers. The dose of 1.55 × 10 UFC LGG/fish/d promoted intestinal colonization. Group EP presented lower hepatic lipid accumulation, lower expression, and higher expression when compared to group E. Supplementation with LGG was protective for hepatic steatosis in ALD model. In addition, LGG influenced the modulation of the inflammatory response and markers of gut permeability, improving the gut barrier structure.
酒精性肝病 (ALD) 是导致肝脏疾病死亡的主要原因之一。在其发病机制中涉及的因素包括炎症和肠道通透性增加。本研究旨在评估 GG (LGG) 对斑马鱼 ALD 实验模型中肝脂质积累、炎症小体激活和肠道通透性标志物的影响。进行了一项实验以评估能够促进肠道定植的有效 LGG 剂量。将动物分为三组(每组 64 只):乙醇组 (E)、乙醇+益生菌组 (EP) 和对照组 (C)。E 组和 EP 组暴露于 0.5%乙醇浓度 28 天。在此期间结束时,处死动物,收集肝脏进行油红染色和炎症小体系统评估。收集肠道用于评估肠道通透性标志物。1.55×10 UFC LGG/鱼/天的剂量可促进肠道定植。与 E 组相比,EP 组肝脂质积累减少, 表达降低, 表达升高。LGG 补充对 ALD 模型中的肝脂肪变性具有保护作用。此外,LGG 影响炎症反应和肠道通透性标志物的调节,改善肠道屏障结构。