Mihalyi E
Department of Clinical Pathology, National Institutes of Health, Besthesda, Maryland 20892.
Biochemistry. 1988 Feb 9;27(3):976-82. doi: 10.1021/bi00403a021.
Kinetic data on the release of fibrinopeptides A and B from bovine fibrinogen by human thrombin were obtained at high fibrinogen concentrations, within the 0.8-8.8% range (0.227 X 10(-4) to 2.60 X 10(-4) M), at 25 degrees C, pH 7.26, 0.30 ionic strength, and 10(-4) M free Ca2+ concentration. Release of fibrinopeptide A followed strictly first-order kinetics at all concentrations, in spite of the fact that the highest concentration was 26 times larger than the value of KM found in the literature. This behavior can be explained by inhibition of thrombin by the reaction products, with KI = KM. The equation describing the course of the reaction under these conditions can be rearranged into a linear relationship between 1/kobsd and substrate concentration. The slope of the line is equal to 1/kcat and the intercept to KM/kcat. The data points fell accurately on a straight line, and with the parameters of the latter, kcat and KM were calculated as (6.3 +/- 0.11) X 10(-10) M s-1 (unit of thrombin)-1 L-1 and (11.0 +/- 3.0) X 10(-6) M, respectively. These values agree well with those found in the literature. Release of fibrinopeptide B follows complex kinetics. Higgins et al. [Higgins, D. L., Lewis, S.D., & Shafer, J.A. (1983) J. Biol. Chem. 258, 9276-9282] suggested that it can be described as the result of two consecutive reactions, the first one being the release of fibrinopeptide A and the second one of fibrinopeptide B from those molecules that have already lost fibrinopeptide A in the previous step.(ABSTRACT TRUNCATED AT 250 WORDS)
在高纤维蛋白原浓度(0.8 - 8.8%范围,即0.227×10⁻⁴至2.60×10⁻⁴ M)、25℃、pH 7.26、离子强度0.30以及游离Ca²⁺浓度10⁻⁴ M的条件下,获取了人凝血酶从牛纤维蛋白原释放纤维蛋白肽A和B的动力学数据。尽管最高浓度比文献中报道的KM值大26倍,但在所有浓度下,纤维蛋白肽A的释放都严格遵循一级动力学。这种行为可以用反应产物对凝血酶的抑制来解释,其抑制常数KI = KM。描述该条件下反应进程的方程可重新整理为1/kobsd与底物浓度之间的线性关系。直线的斜率等于1/kcat,截距等于KM/kcat。数据点精确地落在一条直线上,根据后者的参数,计算出kcat和KM分别为(6.3 ± 0.11)×10⁻¹⁰ M s⁻¹(凝血酶单位)⁻¹ L⁻¹和(11.0 ± 3.0)×10⁻⁶ M。这些值与文献中报道的值非常吻合。纤维蛋白肽B的释放遵循复杂的动力学。希金斯等人[希金斯,D.L.,刘易斯,S.D.,& 谢弗,J.A.(1983年)《生物化学杂志》258,9276 - 9282]认为,它可以被描述为两个连续反应的结果,第一个反应是纤维蛋白肽A的释放,第二个反应是从那些在第一步已经失去纤维蛋白肽A的分子中释放纤维蛋白肽B。