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双{[氨基-(亚氨基鎓基)甲基]脲}四{2-[(二甲基氨基)(亚氨基鎓基)甲基]胍}二μ-氧代-四μ-氧代-十四μ-氧代-八氧化十钒(V)四水合物

Bis{[amino-(iminium-yl)meth-yl]urea} tetra-kis-{2-[(di-methyl-amino)(iminium-yl)meth-yl]guanidine} di-μ-oxido-tetra-μ-oxido-tetra-deca-μ-oxido-octa-oxidodeca-vanadium(V) tetra-hydrate.

作者信息

Pérez-Benítez Aarón, Ariza-Ramírez Jorge Luis, Fortis-Valera Monserrat, Arroyo-Carmona Rosa Elena, Martínez de la Luz María Isabel, Ramírez-Contreras Diego, Bernès Sylvain

机构信息

Facultad de Ciencias Químicas, Benemérita Universidad Autónoma de Puebla, 72570, Puebla, Mexico.

Instituto de Física, Benemérita Universidad Autónoma de Puebla, 72570 Puebla, Pue., Mexico.

出版信息

IUCrdata. 2022 Jun 24;7(Pt 6):x220627. doi: 10.1107/S2414314622006277. eCollection 2022 Jun.

Abstract

The title compound, (CHN)(CHNO)[VO]·4HO, is a by-product obtained by reacting ammonium metavanadate(V), metformin hydro-chloride and acetic acid in the presence of sodium hypochlorite, at pH = 5. The crystal structure comprises a deca-vanadate(V) anion (VO) lying on an inversion centre in space group , while cations and solvent water mol-ecules are placed in general positions, surrounding the anion, and forming numerous N-H⋯O and O-H⋯O hydrogen bonds. Metforminium (CHN) and guanylurea (CHNO) cations display the expected shape. Inter-estingly, in physiology the latter cation is known to be the main metabolite of the former one. The reported structure thus supports the role of sodium hypochlorite as an oxidizing reagent being able to degrade metformin hydro-chloride to form guanylurea.

摘要

标题化合物(CHN)(CHNO)[VO]·4HO是在pH = 5的条件下,偏钒酸铵(V)、盐酸二甲双胍与乙酸在次氯酸钠存在下反应得到的副产物。晶体结构包含一个位于空间群对称中心的十钒酸根(V)阴离子(VO),而阳离子和溶剂水分子处于一般位置,围绕阴离子排列,并形成大量N-H⋯O和O-H⋯O氢键。二甲双胍鎓(CHN)和胍基脲(CHNO)阳离子呈现出预期的形状。有趣的是,在生理学中,已知后一种阳离子是前一种阳离子的主要代谢产物。因此,所报道的结构支持了次氯酸钠作为一种能够将盐酸二甲双胍降解形成胍基脲的氧化试剂的作用。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/eea0/9462036/c4e909eea7b5/x-07-x220627-fig1.jpg

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