Department of Bioengineering, University of California-San Diego, La Jolla, California, USA.
Department of Genetics, University of Cambridge, Cambridge, United Kingdom.
mSphere. 2024 Jul 30;9(7):e0013924. doi: 10.1128/msphere.00139-24. Epub 2024 Jun 21.
Gene knockout studies suggest that ~300 genes in a bacterial genome and ~1,100 genes in a yeast genome cannot be deleted without loss of viability. These single-gene knockout experiments do not account for negative genetic interactions, when two or more genes can each be deleted without effect, but their joint deletion is lethal. Thus, large-scale single-gene deletion studies underestimate the size of a minimal gene set compatible with cell survival. In yeast , the viability of all possible deletions of gene pairs (2-tuples), and of some deletions of gene triplets (3-tuples), has been experimentally tested. To estimate the size of a yeast minimal genome from that data, we first established that finding the size of a minimal gene set is equivalent to finding the minimum vertex cover in the lethality (hyper)graph, where the vertices are genes and (hyper)edges connect -tuples of genes whose joint deletion is lethal. Using the Lovász-Johnson-Chvatal greedy approximation algorithm, we computed the minimum vertex cover of the synthetic-lethal 2-tuples graph to be 1,723 genes. We next simulated the genetic interactions in 3-tuples, extrapolating from the existing triplet sample, and again estimated minimum vertex covers. The size of a minimal gene set in yeast rapidly approaches the size of the entire genome even when considering only synthetic lethalities in -tuples with small . In contrast, several studies reported successful experimental reductions of yeast and bacterial genomes by simultaneous deletions of hundreds of genes, without eliciting synthetic lethality. We discuss possible reasons for this apparent contradiction.IMPORTANCEHow can we estimate the smallest number of genes sufficient for a unicellular organism to survive on a rich medium? One approach is to remove genes one at a time and count how many of such deletion strains are unable to grow. However, the single-gene knockout data are insufficient, because joint gene deletions may result in negative genetic interactions, also known as synthetic lethality. We used a technique from graph theory to estimate the size of minimal yeast genome from partial data on synthetic lethality. The number of potential synthetic lethal interactions grows very fast when multiple genes are deleted, revealing a paradoxical contrast with the experimental reductions of yeast genome by ~100 genes, and of bacterial genomes by several hundreds of genes.
基因敲除研究表明,在细菌基因组中约有 300 个基因,在酵母基因组中约有 1100 个基因不能被删除而不丧失生存能力。这些单基因敲除实验并未考虑到负遗传相互作用,即两个或更多基因可以单独删除而没有影响,但它们的联合删除是致命的。因此,大规模的单基因删除研究低估了与细胞存活相容的最小基因集的大小。在酵母中,已经通过实验测试了所有可能的基因对(双联体)的缺失和一些基因三联体(三联体)的缺失的生存能力。为了从该数据中估计酵母最小基因组的大小,我们首先确定找到最小基因集的大小等同于在致死性(超)图中找到最小顶点覆盖,其中顶点是基因,(超)边连接联合删除是致命的基因的基因对。使用 Lovász-Johnson-Chvatal 贪婪近似算法,我们计算出合成致死性 2-联体图的最小顶点覆盖数为 1723 个基因。我们接下来模拟了 3-联体中的遗传相互作用,从现有的三联体样本中推断,并再次估计最小顶点覆盖数。即使只考虑小的 -联体的合成致死性,酵母中最小基因集的大小也迅速接近整个基因组的大小。相比之下,有几项研究报告说,通过同时删除数百个基因,成功地减少了酵母和细菌的基因组,而没有引起合成致死性。我们讨论了这种明显矛盾的可能原因。
重要性
我们如何估计单细胞生物在丰富培养基上生存所需的最小基因数?一种方法是一次删除一个基因,并计算有多少这样的缺失菌株无法生长。然而,单基因敲除数据是不够的,因为联合基因缺失可能导致负遗传相互作用,也称为合成致死性。我们使用图论中的一种技术,根据合成致死性的部分数据来估计酵母最小基因组的大小。当删除多个基因时,潜在的合成致死相互作用的数量增长非常快,这与通过约 100 个基因减少酵母基因组和通过数百个基因减少细菌基因组的实验形成了鲜明的对比。