Mann M B, Smith H O
Nucleic Acids Res. 1977 Dec;4(12):4211-21. doi: 10.1093/nar/4.12.4211.
The methylases M.HaeIII and M.HpaII recognize the tetranucleotide sequences [Formula: see text] and [Formula: see text] respectively, in DNA, and transfer a methyl group from S-adenosylmethionine to the 5-position of cytosine on each strand as indicated by the asterisks. Restriction endonuclease R.HaeIII does not cleave the methylated sequence [Formula: see text] but can cleave [Formula: see text] in which methylation is introduced on the unnatural external cytosine positions. Similarly, R.HpaII does not cleave [Formula: see text] but can cleave [Formula: see text].Images
甲基化酶M.HaeIII和M.HpaII分别识别DNA中的四核苷酸序列[公式:见正文]和[公式:见正文],并将S-腺苷甲硫氨酸中的甲基转移到每条链上胞嘧啶的5位,如星号所示。限制性内切酶R.HaeIII不能切割甲基化序列[公式:见正文],但可以切割[公式:见正文],其中甲基化是在非天然的外部胞嘧啶位置引入的。同样,R.HpaII不能切割[公式:见正文],但可以切割[公式:见正文]。图片