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酒精性酸中毒的治疗:葡萄糖与磷的作用

Treatment of alcoholic acidosis: the role of dextrose and phosphorus.

作者信息

Miller P D, Heinig R E, Waterhouse C

出版信息

Arch Intern Med. 1978 Jan;138(1):67-72.

PMID:619832
Abstract

We have made serial metabolic observations in 18 acute episodes of alcoholic ketoacidosis in ten patients. Data from patients treated with only saline initially were compared to data from patients who received modest amounts of intravenous dextrose (7.0 to 7.5 gm/hr). More rapid improvement in the acidotic state was seen in the latter group (P less than .001). The quicker decline in absolute levels and ratio of beta-hydroxybutyrate to acetoacetate when glucose was given suggests that this treatment induced mitochondrial oxidation of the reduced form of nicotinamide adenine dinucleotide (NADH). Since phosphorus is a critical cofactor necessary for NADH oxidation and the glucose-induced correction of the acidosis was associated with a rapid decline in serum phosphorus from an initial mean of 6.79 +/- .82 mg/100 ml SEM to 0.96 +/- 0.12 mg/100 ml in 24 hours, we propose that glucose enhanced the mitochondrial capacity to oxidize NADH by increasing hepatocyte phosphorus. This effect combined with decline in free fatty acid levels results in reversal of acidosis. Our data suggest that glucose provides the safest, most effective treatment for this disorder; addition of either insulin or bicarbonate is usually unnecessary.

摘要

我们对10例患者的18次急性酒精性酮症酸中毒发作进行了系列代谢观察。将最初仅用生理盐水治疗的患者数据与接受适量静脉输注葡萄糖(7.0至7.5克/小时)的患者数据进行比较。后一组患者的酸中毒状态改善更快(P小于0.001)。给予葡萄糖时,β-羟丁酸与乙酰乙酸的绝对水平及比值下降更快,这表明该治疗诱导了烟酰胺腺嘌呤二核苷酸(NADH)还原形式的线粒体氧化。由于磷是NADH氧化所必需的关键辅助因子,且葡萄糖诱导的酸中毒纠正与血清磷在24小时内从初始平均值6.79±0.82毫克/100毫升标准误迅速降至0.96±0.12毫克/100毫升有关,我们提出葡萄糖通过增加肝细胞磷含量来增强线粒体氧化NADH的能力。这种作用与游离脂肪酸水平下降相结合,导致酸中毒逆转。我们的数据表明,葡萄糖为这种疾病提供了最安全、最有效的治疗方法;通常无需添加胰岛素或碳酸氢盐。

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