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葡萄球菌肠毒素B的染色体位点

Chromosomal locus for staphylococcal enterotoxin B.

作者信息

Shafer W M, Iandolo J J

出版信息

Infect Immun. 1978 Apr;20(1):273-8. doi: 10.1128/iai.20.1.273-278.1978.

Abstract

The genetic locus of staphylococcal enterotoxin B (SEB) was investigated in the Staphylococcus aureus food-poisoning isolates, strains S6 and 277. Direct neutral sucrose gradient centrifugation analysis of sodium dodecyl sulfate-sodium chloride-mediated cleared lysates demonstrated that strain S6 contained a single 37S plasmid. Transductional analysis revealed that the 37S plasmid in S6 encoded for cadmium resistance (Cad) but not SEB. Additionally, elimination of cadmium resistance in S6 provided a plasmid-negative derivative that produced SEB at the same level as the parent. Examination of strain 277 showed two plasmids, a 37S species encoding for penicillin resistance (Penr) and a 21S species containing the gene(s) responsible for tetracycline resistance (Tetr). Elimination of the 37S, penr plasmid in 277 had no effect on SEB production, whereas introduction of the 21S tetr plasmid via transformation into strain 8325 (SEB--) did not confer enterotoxigenesis upon the transformants. The data obtained in this investigation suggest that the SEB gene(s) in these food-poisoning isolates of S. aureus is chromosomal.

摘要

对金黄色葡萄球菌食物中毒分离株S6和277中葡萄球菌肠毒素B(SEB)的基因位点进行了研究。通过十二烷基硫酸钠 - 氯化钠介导的清亮裂解物的直接中性蔗糖梯度离心分析表明,菌株S6含有一个单一的37S质粒。转导分析显示,S6中的37S质粒编码镉抗性(Cad)但不编码SEB。此外,消除S6中的镉抗性得到了一个质粒阴性衍生物,其产生SEB的水平与亲本相同。对菌株277的检测显示有两个质粒,一个37S质粒编码青霉素抗性(Penr),一个21S质粒含有负责四环素抗性(Tetr)的基因。消除277中的37S、penr质粒对SEB的产生没有影响,而通过转化将21S tetr质粒导入菌株8325(SEB--)并没有使转化体产生肠毒素。本研究获得的数据表明,这些金黄色葡萄球菌食物中毒分离株中的SEB基因位于染色体上。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/ab86/421583/d3a8558b4804/iai00196-0287-a.jpg

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