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有限群体中两个随机选择的顺反子之间核苷酸差异的分布。

Distribution of nucleotide differences between two randomly chosen cistrons in a finite population.

作者信息

Li W H

出版信息

Genetics. 1977 Feb;85(2):331-7. doi: 10.1093/genetics/85.2.331.

Abstract

Watterson's (1975) formula for the steady-state distribution of the number of nucleotide differences between two randomly chosen cistrons in a finite population has been extended to transient states. The rate for the mean of this distribution to approach its equilibrium value is 1/2N and independent of mutation rate, but that for the variance is dependent on mutation rate, where N denotes the effective population size. Numerical computations show that if the heterozygosity (i.e., the probability that two cistrons are different) is low, say of the order of 0.1 or less, the probability that two cistrons differ at two or more nucleotide sites is less than 10 percent of the heterozygosity, whereas this probability may be as high as 50 percent of the heterozygosity if the heterozygosity is 0.5. A simple estimate for the mean number (-d) of site differences between cistrons is d = h/(1 - h) where h is the heterozygosity. At equilibrium, the probability that two cistrons differ by more than one site is equal to h2, the square of heterozygosity.

摘要

沃特森(1975年)提出的关于有限群体中两个随机选择的顺反子之间核苷酸差异数稳态分布的公式已扩展到瞬态。该分布均值趋近其平衡值的速率为1/2N,且与突变率无关,但方差的速率则取决于突变率,其中N表示有效群体大小。数值计算表明,如果杂合度(即两个顺反子不同的概率)较低,比如在0.1或更低的量级,那么两个顺反子在两个或更多核苷酸位点存在差异的概率小于杂合度的10%,而如果杂合度为0.5,此概率可能高达杂合度的50%。顺反子之间位点差异平均数(-d)的一个简单估计是d = h/(1 - h),其中h是杂合度。在平衡状态下,两个顺反子差异超过一个位点的概率等于h²,即杂合度的平方。

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