Pincus David L, Thirumalai D
Department of Chemistry and Biochemistry, University of Maryland, College Park, Maryland 20742, USA.
J Phys Chem B. 2009 Jan 8;113(1):359-68. doi: 10.1021/jp807755b.
The interiors of cells are crowded, thus making it important to assess the effects of macromolecules on the folding of proteins. Using the self-organized polymer (SOP) model, which is a coarse-grained representation of polypeptide chains, we probe the mechanical stability of ubiquitin (Ub) monomers and trimers ((Ub)(3)) in the presence of monodisperse spherical crowding agents. Crowding increases the volume fraction (Phi(c))-dependent average force (f(u)(Phi(c))), relative to the value at Phi(c) = 0, needed to unfold Ub and the polyprotein. For a given Phi(c), the values of f(u)(Phi(c)) increase as the diameter (sigma(c)) of the crowding particles decreases. The average unfolding force f(u)(Phi(c)) depends on the ratio D/R(g), where D approximately sigma(c)(pi/6Phi(c))(1/3), with R(g) being the radius of gyration of Ub (or (Ub)(3)) in the unfolded state. Examination of the unfolding pathways shows that, relative to Phi(c) = 0, crowding promotes reassociation of ruptured secondary structural elements. Both the nature of the unfolding pathways and f(u)(Phi(c)) for (Ub)(3) are altered in the presence of crowding particles, with the effect being most dramatic for the subunit that unfolds last. We predict, based on SOP simulations and theoretical arguments, that f(u)(Phi(c)) approximately Phi(c)(1/3nu), where nu is the Flory exponent that describes the unfolded (random coil) state of the protein.
细胞内部空间拥挤,因此评估大分子对蛋白质折叠的影响很重要。我们使用自组装聚合物(SOP)模型(这是一种多肽链的粗粒度表示),在单分散球形拥挤剂存在的情况下,探究泛素(Ub)单体和三聚体((Ub)(3))的机械稳定性。与在Phi(c) = 0时的值相比,拥挤增加了展开Ub和多蛋白所需的与体积分数(Phi(c))相关的平均力(f(u)(Phi(c)))。对于给定的Phi(c),f(u)(Phi(c))的值随着拥挤颗粒直径(sigma(c))的减小而增加。平均展开力f(u)(Phi(c))取决于D/R(g)的比值,其中D约为sigma(c)(pi/6Phi(c))(1/3),R(g)是Ub(或(Ub)(3))在未折叠状态下的回转半径。对展开途径的研究表明,相对于Phi(c) = 0,拥挤促进了断裂二级结构元件的重新结合。在存在拥挤颗粒的情况下,(Ub)(3)的展开途径性质和f(u)(Phi(c))都会改变,对最后展开的亚基影响最为显著。基于SOP模拟和理论论证,我们预测f(u)(Phi(c))约为Phi(c)(1/3nu),其中nu是描述蛋白质未折叠(无规卷曲)状态的弗洛里指数。