Institute for World Health Development, Mukogawa Women's University, Nishinomiya, 6638143, Japan.
J Biomed Sci. 2010 Aug 24;17 Suppl 1(Suppl 1):S43. doi: 10.1186/1423-0127-17-S1-S43.
Since our previous report on WHO CARDIAC Study data demonstrated that 24-hour urinary (24U) taurine (Tau) excretion was a useful biomarker of seafood (SF) intake and inversely related to the mortality rates of stroke and coronary heart diseases in the world, we determined that SF is important in the risk reduction of lifestyle related-diseases. The amounts of dietary SF intake are so far estimated from a nutritional survey or 24U Tau excretion.The sodium/potassium ratio of spot urine (SU) and the 24U ratio were reported to be significantly correlated with. Therefore, we presently examined the relationship of Tau excretion in the morning SU with 24U Tau for simplifying the population comparison and the follow-up of SF intake changes in the process of food education program (FEP).
After informed consent was obtained, 54 children aged 6-11 years (Children) and 193 adolescents aged 13-18 years (Adolescents) participated in collecting precisely 24U and SU of the first urination on the same day and answered the questionnaire including age and height and weight measurements. The urine samples were measured for creatinine (Cre) and Tau, and the association of these between 24U and SU were analyzed.
The success rates of 24U sampling were very high in Children and Adolescents, 96.4% and 82.4%, respectively. From the result of the multiple regression analysis of SU Tau/Cre and weight we obtained formulas for predicting 24U Tau excretion in Children and Adolescents as follows: Children: 24U Tau = 16.3 (weight) + 314.3 (SU Tau/Cre) -175.2; and Adolescents: 24U Tau = 20.2 (weight) + 644.7 (SU Tau/Cre) - 569.4.
The present study established the regression equation to estimate 24U Tau excretion from SU Tau/Cre and weight. These formulas are expected to contribute to the estimation of fish and SF intake and the follow-up of the change of the dietary behavior by FEP in Children and Adolescents.
由于我们之前报告的世界卫生组织心脏研究数据表明，24 小时尿（24U）牛磺酸（Tau）排泄量是海鲜（SF）摄入量的有用生物标志物，与中风和冠心病的死亡率呈反比，我们确定 SF 对降低与生活方式相关的疾病风险很重要。到目前为止，SF 的饮食摄入量是通过营养调查或 24U Tau 排泄量来估计的。有报道称，即时尿（SU）的钠/钾比值和 24U 比值与 Tau 排泄量显著相关。因此，我们目前检查了早晨 SU 中 Tau 排泄量与 24U Tau 的关系，以便简化人群比较和在食品教育计划（FEP）过程中简化 SF 摄入量变化的随访。
在获得知情同意后，54 名 6-11 岁的儿童（儿童）和 193 名 13-18 岁的青少年（青少年）参与了同一天准确收集 24U 和第一次排尿的 SU，并回答了包括年龄、身高和体重测量在内的问卷。对尿样进行肌酐（Cre）和 Tau 检测，并分析这些 24U 和 SU 之间的关联。
儿童和青少年的 24U 采样成功率非常高，分别为 96.4%和 82.4%。根据 SU Tau/Cre 和体重的多元回归分析结果，我们得出了预测儿童和青少年 24U Tau 排泄量的公式如下：儿童：24U Tau = 16.3（体重）+314.3（SU Tau/Cre）-175.2；青少年：24U Tau = 20.2（体重）+644.7（SU Tau/Cre）-569.4。
本研究建立了从 SU Tau/Cre 和体重估计 24U Tau 排泄量的回归方程。这些公式有望为儿童和青少年的鱼类和 SF 摄入量估计以及通过 FEP 对饮食行为变化的随访做出贡献。
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