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双吡啶钌配合物催化醇和水形成羧酸酯的反应机理:计算研究。

Mechanism of the formation of carboxylate from alcohols and water catalyzed by a bipyridine-based ruthenium complex: a computational study.

机构信息

Department of Chemistry, Texas A&M University , College Station, Texas 77843-3255, United States.

出版信息

J Am Chem Soc. 2014 Jan 8;136(1):383-95. doi: 10.1021/ja410541v. Epub 2013 Dec 24.

DOI:10.1021/ja410541v
PMID:24328295
Abstract

The catalytic mechanism for oxidizing alcohols to carboxylate in basic aqueous solution by the bipyridine-based ruthenium complex 2 (BIPY-PNN)Ru(H)(Cl)(CO) (Nat. Chem. 2013, 5, 122) is investigated by density functional theory (DFT) with the ωB97X-D functional. Using water as the oxygen donor with liberation of dihydrogen represents a safe and clean process for such oxidations. Under NaOH, the active catalyst is 3 (BIPY-PNN)Ru(H)(CO). Four steps are involved: dehydrogenation of alcohol to aldehyde (Step 1); coupling of aldehyde and water to form the gem-diol (Step 2); dehydrogenation of gem-diol to carboxylic acid (Step 3); and deprotonation of carboxylic acid to carboxylate anion under base (Step 4). The dehydrogenations of alcohol (Step 1) and gem-diol (Step 3) prefer the double hydrogen transfer mechanism to the β-H elimination mechanism. The coupling of aldehyde and water (Step 2) proceeds through cleavage of water by catalyst 3 followed by concerted hydroxyl and hydrogen transfer to the aldehyde. The formation of the carboxylate anion occurs via direct deprotonation of the carboxylic acid under base (Step 4), while in the absence of base a stable carboxylic acid-addition complex 6 was formed. Added base was found to play important roles in the generation of catalyst 3 from both the stable carboxylic acid-addition complex 6 and its chloride precursor complex 2. The chemoselectivity for the formation of carboxylic acid rather than ester is ascribed to the favorable cleavage of water and the subsequent generation of the stable carboxylate anion that leads to carboxylic acid upon acidification.

摘要

基于联吡啶的钌配合物 2(BIPY-PNN)Ru(H)(Cl)(CO)(Nat.Chem. 2013, 5, 122)在碱性水溶液中将醇氧化为羧酸的催化机制通过密度泛函理论(DFT)与 ωB97X-D 函数进行了研究。使用水作为供氢体并释放氢气代表了此类氧化的安全清洁过程。在 NaOH 存在下,活性催化剂为 3(BIPY-PNN)Ru(H)(CO)。涉及四个步骤:醇脱氢为醛(步骤 1);醛与水偶联形成偕二醇(步骤 2);偕二醇脱氢为羧酸(步骤 3);在碱下羧酸去质子化为羧酸根阴离子(步骤 4)。醇(步骤 1)和偕二醇(步骤 3)的脱氢更倾向于双氢转移机制而不是β-H 消除机制。醛与水的偶联通过催化剂 3 裂解水,然后协同羟基和氢转移到醛进行。羧酸根阴离子的形成通过羧酸在碱下直接去质子化发生(步骤 4),而在没有碱的情况下形成稳定的羧酸加成配合物 6。添加的碱在从稳定的羧酸加成配合物 6 和其氯前体配合物 2 生成催化剂 3 方面均发挥重要作用。形成羧酸而不是酯的化学选择性归因于水的有利裂解以及随后生成稳定的羧酸根阴离子,酸化后得到羧酸。

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