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人胎盘碱性磷酸酶基因的Pst I限制性片段长度多态性:孟德尔分离及基因突变位点的定位

Pst I restriction fragment length polymorphism of human placental alkaline phosphatase gene: Mendelian segregation and localization of mutation site in the gene.

作者信息

Tsavaler L, Penhallow R C, Sussman H H

机构信息

Department of Pathology, Stanford University, School of Medicine, CA 94305.

出版信息

Proc Natl Acad Sci U S A. 1988 Oct;85(20):7680-4. doi: 10.1073/pnas.85.20.7680.

Abstract

The pattern of inheritance of a Pst I restriction fragment length polymorphism (RFLP) of the human placental alkaline phosphatase gene was studied in nine nuclear families by Southern blot hybridization analysis of genomic DNA. The dimorphic RFLP is defined by the presence of allelic fragments 1.0 kilobase and 0.8 kilobase long. The results of this study show that the two alleles of the PstI RFLP of the placental alkaline phosphatase gene segregate as codominant traits according to Mendelian expectations. For a polymorphism to be useful as a genetic marker the probability that an offspring is informative (PIC) must be at least 0.15. The allelic frequency of the 1.0-kilobase allele is 0.21, which correlates to a probability that an offspring is informative of 0.275 and is indicative of a useful polymorphism. By using probes derived from different regions of the placental alkaline phosphatase cDNA, the mutated Pst I site causing the RFLP was located in the penultimate intron 2497 base pairs downstream from the transcriptional initiation site.

摘要

通过对基因组DNA进行Southern印迹杂交分析,在9个核心家庭中研究了人胎盘碱性磷酸酶基因Pst I限制性片段长度多态性(RFLP)的遗传模式。这种双态RFLP由1.0千碱基和0.8千碱基长的等位基因片段的存在来定义。本研究结果表明,胎盘碱性磷酸酶基因PstI RFLP的两个等位基因按照孟德尔预期作为共显性性状分离。对于一种多态性要作为遗传标记有用,后代具有信息性的概率(PIC)必须至少为0.15。1.0千碱基等位基因的等位基因频率为0.21,这与后代具有信息性的概率0.275相关,表明这是一种有用的多态性。通过使用源自胎盘碱性磷酸酶cDNA不同区域的探针,导致RFLP的突变Pst I位点位于转录起始位点下游2497个碱基对的倒数第二个内含子中。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/1164/282256/17253f3d5c2d/pnas00299-0266-a.jpg

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