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人类泛素多基因家族:一些基因包含多个直接重复的泛素编码序列。

The human ubiquitin multigene family: some genes contain multiple directly repeated ubiquitin coding sequences.

作者信息

Wiborg O, Pedersen M S, Wind A, Berglund L E, Marcker K A, Vuust J

出版信息

EMBO J. 1985 Mar;4(3):755-9. doi: 10.1002/j.1460-2075.1985.tb03693.x.

Abstract

Ubiquitin coding sequences were isolated from a human genomic library and two cDNA libraries. One human ubiquitin gene consists of 2055 nucleotides and codes for a polyprotein consisting of 685 amino acid residues. The polyprotein contains nine direct repeats of the ubiquitin amino acid sequence and the last ubiquitin sequence is extended with an additional valyl residue at the C-terminal end. No spacer sequences separate the ubiquitin repeats and the coding regions are not interrupted by intervening sequences. This particular gene is transcribed since cDNAs corresponding to the genomic sequence have been isolated. At least two more types of ubiquitin genes are encoded in the human genome, one coding for an ubiquitin monomer while another presumably codes for three or four direct repeats of the ubiquitin sequence. Human DNA contains many copies of the ubiquitin sequence. Ubiquitin is therefore encoded in the human genome as a multigene family.

摘要

泛素编码序列是从一个人类基因组文库和两个cDNA文库中分离出来的。一个人类泛素基因由2055个核苷酸组成,编码一种由685个氨基酸残基组成的多聚蛋白。该多聚蛋白包含九个泛素氨基酸序列的直接重复,并且最后一个泛素序列在C末端延伸有一个额外的缬氨酸残基。没有间隔序列分隔泛素重复序列,并且编码区域不被插入序列打断。由于已经分离出与基因组序列相对应的cDNA,所以这个特定的基因被转录。人类基因组中至少还编码另外两种类型的泛素基因,一种编码泛素单体,而另一种可能编码泛素序列的三个或四个直接重复。人类DNA包含许多泛素序列的拷贝。因此,泛素在人类基因组中作为一个多基因家族被编码。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/b1cb/554252/c8d9ab7c2015/emboj00268-0177-a.jpg

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