Department of Biology, Indiana University, Bloomington, Indiana 47405.
School of Informatics, Computing, and Engineering, Indiana University, Bloomington, Indiana 47405.
Genetics. 2018 Aug;209(4):1043-1054. doi: 10.1534/genetics.117.300515. Epub 2018 Jun 15.
When the DNA polymerase that replicates the chromosome, DNA polymerase III, makes an error, there are two primary defenses against mutation: proofreading by the ϵ subunit of the holoenzyme and mismatch repair. In proofreading-deficient strains, mismatch repair is partially saturated and the cell's response to DNA damage, the SOS response, may be partially induced. To investigate the nature of replication errors, we used mutation accumulation experiments and whole-genome sequencing to determine mutation rates and mutational spectra across the entire chromosome of strains deficient in proofreading, mismatch repair, and the SOS response. We report that a proofreading-deficient strain has a mutation rate 4000-fold greater than wild-type strains. While the SOS response may be induced in these cells, it does not contribute to the mutational load. Inactivating mismatch repair in a proofreading-deficient strain increases the mutation rate another 1.5-fold. DNA polymerase has a bias for converting G:C to A:T base pairs, but proofreading reduces the impact of these mutations, helping to maintain the genomic G:C content. These findings give an unprecedented view of how polymerase and error-correction pathways work together to maintain 's low mutation rate of 1 per 1000 generations.
当复制染色体的 DNA 聚合酶,即 DNA 聚合酶 III 发生错误时,有两个主要的防御机制来防止突变:全酶的 ε 亚基的校对和错配修复。在缺乏校对的菌株中,错配修复部分饱和,细胞对 DNA 损伤的反应,即 SOS 反应,可能部分被诱导。为了研究复制错误的性质,我们使用突变积累实验和全基因组测序来确定整个染色体的突变率和突变谱在缺乏校对、错配修复和 SOS 反应的菌株中。我们报告说,一个缺乏校对的菌株的突变率比野生型菌株高 4000 倍。虽然 SOS 反应可能在这些细胞中被诱导,但它不会增加突变负荷。在缺乏校对的菌株中失活错配修复会使突变率再增加 1.5 倍。DNA 聚合酶有一种将 G:C 转换为 A:T 碱基对的偏好,但校对会降低这些突变的影响,有助于维持基因组的 G:C 含量。这些发现提供了一个前所未有的视角,了解聚合酶和纠错途径如何协同工作,以维持基因组每 1000 代 1 次的低突变率。