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河豚毒素与哺乳动物无髓神经纤维在平衡状态下的相互作用。

The interaction at equilibrium between tetrodotoxin and mammalian non-myelinated nerve fibres.

作者信息

Colquhoun D, Ritchie J M

出版信息

J Physiol. 1972 Mar;221(3):533-53. doi: 10.1113/jphysiol.1972.sp009766.

Abstract
  1. As a preliminary to chemical studies an estimate has been made of the equilibrium dissociation constant (K) for the interaction of tetrodotoxin (TTX) with the non-myelinated fibres of the rabbit desheathed vagus nerve.2. TTX causes a parallel shift to the right of the curves obtained when either the height or the conduction velocity of the compound action potential are plotted against the logarithm of the external sodium concentration.3. A model has been formulated based on the independence principle and the Hodgkin-Huxley theory, and the experimental results shown to be consistent with it. On this basis, and on the assumptions that one TTX molecule blocks one sodium channel, and that binding is Langmuir, K was estimated to be about 3-5 nM at about 20 degrees C. Other simple non-Langmuir models gave essentially similar low values for K.4. An alternative method of computing K that makes rather different assumptions gives a similar low value.5. Despite the low value for K, a TTX concentration of at least 100 nM is needed to block conduction completely and this seems to be related to the fact that conduction is not completely blocked until the external sodium concentration falls below 7% of its value in normal Locke.6. The minimum sodium concentration needed to support conduction increased with temperature.
摘要
  1. 作为化学研究的前奏,已对河豚毒素(TTX)与兔去鞘迷走神经无髓纤维相互作用的平衡解离常数(K)进行了估算。

  2. 当将复合动作电位的高度或传导速度相对于外部钠浓度的对数作图时,TTX会使所得曲线向右平行移动。

  3. 基于独立性原理和霍奇金-赫胥黎理论建立了一个模型,实验结果表明与该模型一致。在此基础上,并假设一个TTX分子阻断一个钠通道,且结合为朗缪尔结合,在约20℃时K估计约为3 - 5 nM。其他简单的非朗缪尔模型给出的K值也基本相似且较低。

  4. 另一种计算K的方法做出了相当不同的假设,但给出了相似的低值。

  5. 尽管K值较低,但完全阻断传导需要至少100 nM的TTX浓度,这似乎与以下事实有关:直到外部钠浓度降至正常洛克溶液中其值的7%以下时,传导才会被完全阻断。

  6. 支持传导所需的最低钠浓度随温度升高而增加。

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