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用于测定七叶苷水解的快速斑点试验。

Rapid spot test for the determination of esculin hydrolysis.

作者信息

Edberg S C, Gam K, Bottenbley C J, Singer J M

出版信息

J Clin Microbiol. 1976 Aug;4(2):180-4. doi: 10.1128/jcm.4.2.180-184.1976.

Abstract

Esculin hydrolysis is a useful test in the differentiation of both gram-positive and gram-negative bacteria covering a wide spectrum of aerobes, facultative anaerobes, and anaerobes. Commonly utilized methods require a minimum of 18 h of incubation in broth or agar medium and utilize the production of a brown-black compound, due to the combination of ferric ions with the hydrolysis product esculetin, as indicator. A procedure is presented that requires 15 to 30 min for completion and utilizes fluorescence loss as the indicator of hydrolysis. Esculin fluoresces at 366 nm, whereas the hydrolysis product esculetin does not. Over 1,400 strains of gram-positive and gram-negative bacteria were tested. There was 98.4% of correlation between the spot test and esculin broth and 97% correlation with the bile-esculin agar.

摘要

七叶苷水解试验是一种用于鉴别革兰氏阳性菌和革兰氏阴性菌的有用试验,这些细菌涵盖了广泛的需氧菌、兼性厌氧菌和厌氧菌。常用方法需要在肉汤或琼脂培养基中至少培养18小时,并利用铁离子与水解产物七叶亭结合产生的棕黑色化合物作为指示剂。本文介绍了一种15至30分钟即可完成的方法,该方法利用荧光消失作为水解的指示剂。七叶苷在366nm处发荧光,而水解产物七叶亭则不发荧光。对1400多株革兰氏阳性菌和革兰氏阴性菌进行了测试。斑点试验与七叶苷肉汤之间的相关性为98.4%,与胆汁七叶苷琼脂的相关性为97%。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/8620/274422/1a3e58ad4b99/jcm00217-0088-a.jpg

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