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鉴定M6跨膜片段及其侧翼的囊性纤维化跨膜传导调节因子通道内衬残基。

Identification of cystic fibrosis transmembrane conductance regulator channel-lining residues in and flanking the M6 membrane-spanning segment.

作者信息

Cheung M, Akabas M H

机构信息

Center for Molecular Recognition, College of Physicians and Surgeons, Columbia University, New York, New York 10032, USA.

出版信息

Biophys J. 1996 Jun;70(6):2688-95. doi: 10.1016/S0006-3495(96)79838-7.

Abstract

The cystic fibrosis transmembrane conductance regulator (CFTR) forms a chloride channel that is regulated by phosphorylation and ATP binding. Work by others suggested that some residues in the sixth transmembrane segment (M6) might be exposed in the channel and play a role in ion conduction and selectivity. To identify the residues in M6 that are exposed in the channel and the secondary structure of M6, we used the substituted cysteine accessibility method. We mutated to cysteine, one at a time, 24 consecutive residues in and flanking the M6 segment and expressed these mutants in Xenopus oocytes. We determined the accessibility of the engineered cysteines to charged, lipophobic, sulfhydryl-specific methanethiosulfonate (MTS) reagents applied extracellularly. The cysteines substituted for Ile331, Leu333, Arg334, Lys335, Phe337, Ser341, Ile344, Arg347, Thr351, Arg352, and Gln353 reacted with the MTS reagents, and we infer that they are exposed on the water-accessible surface of the protein. From the pattern of the exposed residues we infer that the secondary structure of the M6 segment includes both alpha-helical and extended regions. The diameter of the channel from the extracellular end to the level of Gln353 must be at least 6 A to allow the MTS reagents to reach these residues.

摘要

囊性纤维化跨膜传导调节因子(CFTR)形成一种受磷酸化和ATP结合调控的氯离子通道。其他人的研究表明,第六个跨膜片段(M6)中的一些残基可能暴露在通道中,并在离子传导和选择性方面发挥作用。为了确定M6中暴露在通道中的残基以及M6的二级结构,我们使用了半胱氨酸替代可及性方法。我们将M6片段及其侧翼的24个连续残基逐个突变为半胱氨酸,并在非洲爪蟾卵母细胞中表达这些突变体。我们测定了工程化半胱氨酸对细胞外施加的带电荷、疏脂性、巯基特异性甲硫基磺酸盐(MTS)试剂的可及性。替代Ile331、Leu333、Arg334、Lys335、Phe337、Ser341、Ile344、Arg347、Thr351、Arg352和Gln353的半胱氨酸与MTS试剂发生反应,我们推断它们暴露在蛋白质的水可及表面上。根据暴露残基的模式,我们推断M6片段的二级结构包括α螺旋区域和伸展区域。从细胞外端到Gln353水平的通道直径必须至少为6埃,以使MTS试剂能够到达这些残基。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/b81d/1225248/c3e5525e3f04/biophysj00048-0226-a.jpg

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