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L-1,2-丙二醇比L-乳醛从大肠杆菌中排出得更快。

L-1,2-propanediol exits more rapidly than L-lactaldehyde from Escherichia coli.

作者信息

Zhu Y, Lin E C

机构信息

Department of Microbiology and Molecular Genetics, Harvard Medical School, Boston, Massachusetts 02115.

出版信息

J Bacteriol. 1989 Feb;171(2):862-7. doi: 10.1128/jb.171.2.862-867.1989.

Abstract

Catabolism of the six-carbon compound L-fucose results in formation of dihydroxyacetone phosphate (C-1-to-C-3 fragment) and L-lactaldehyde (C-4-to-C-6 fragment) as intermediates. The fate of lactaldehyde depends on the respiratory growth conditions. Aerobically, lactaldehyde is oxidized to L-lactate by an NAD-linked dehydrogenase (ald product). L-Lactate, in turn, is converted to pyruvate, which enters the general metabolic pool. Anaerobically, lactaldehyde is reduced to L-1,2-propanediol by an NADH-linked oxidoreductase (fucO product). L-1,2-Propanediol is excreted as a terminal fermentation product. In a previous study, we showed that retention of the C-4-to-C-6 fragment of fucose depended on the competition for lactaldehyde by aldehyde dehydrogenase and propanediol oxidoreductase (Y. Zhu and E.C.C. Lin, J. Bacteriol. 169:785-789, 1987). In this study, we compared the wild-type strain and isogenic mutant strains defective in ald, fucO, or both for ability to accumulate radioactivity when incubated with fucose labeled at either the C-1 or the C-6 position. The results showed that although blocking the oxidation of lactaldehyde prevented its assimilation, rapid exit of the 3-carbon unit occurred only when the compound was reduced to propanediol. Moreover, growth experiments on fucose indicated that a double ald fucO mutant accumulated inhibiting concentrations of lactaldehyde. The inner cell membrane therefore appears to be much more permeable to the 3-carbon alcohol than to the 3-carbon aldehyde. The almost instantaneous exit of propanediol appears to be a facilitated process.

摘要

六碳化合物L-岩藻糖的分解代谢会产生磷酸二羟丙酮(C-1至C-3片段)和L-乳醛(C-4至C-6片段)作为中间产物。乳醛的去向取决于呼吸生长条件。在有氧条件下,乳醛被NAD连接的脱氢酶(醛产物)氧化为L-乳酸。L-乳酸继而被转化为丙酮酸,进入一般代谢池。在无氧条件下,乳醛被NADH连接的氧化还原酶(fucO产物)还原为L-1,2-丙二醇。L-1,2-丙二醇作为终末发酵产物被排出。在之前的一项研究中,我们表明岩藻糖C-4至C-6片段的保留取决于醛脱氢酶和丙二醇氧化还原酶对乳醛的竞争(Y. Zhu和E.C.C. Lin,《细菌学杂志》169:785 - 789,1987)。在本研究中,我们比较了野生型菌株以及在ald、fucO或二者均有缺陷的同基因突变菌株在与C-1或C-6位置标记的岩藻糖一起孵育时积累放射性的能力。结果表明,虽然阻断乳醛的氧化会阻止其同化,但只有当该化合物被还原为丙二醇时,三碳单元才会快速排出。此外,以岩藻糖进行的生长实验表明,ald fucO双突变体积累了抑制浓度的乳醛。因此,内膜对三碳醇的通透性似乎比对三碳醛的通透性大得多。丙二醇几乎瞬间排出似乎是一个易化过程。

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