Department of Medicine, Brigham and Women's Hospital, Harvard Medical School, Boston, MA, 02115, USA.
Sci Rep. 2019 Dec 20;9(1):19568. doi: 10.1038/s41598-019-55951-9.
Pyruvate, a pivotal glucose metabolite, is an α-ketoacid that reacts with hydrogen peroxide (HO). Its pharmacological precursor, ethyl pyruvate, has shown anti-inflammatory/anti-tissue injury effects in various animal models of disease, but failed in a multicenter clinical trial. Since rodents, but not humans, can convert ethyl pyruvate to pyruvate in blood plasma, this additional source of extracellular pyruvate may have contributed to the discrepancy between the species. To examine this possibility, we investigated the kinetics of the reaction under biological conditions and determined the second order rate constant k as 2.360 ± 0.198 M s. We then calculated the time required for HO elimination by pyruvate. The results show that, with an average intracellular concentration of pyruvate (150 µM), elimination of 95% HO at normal to pathological concentrations (0.01-50 µM) requires 141-185 min (2.4-3 hour). With 1,000 µM pyruvate, a concentration that can only exist extracellularly or in cell culture media, 95% elimination of HO at 5-200 µM requires 21-25 min. We conclude that intracellular pyruvate, or other α-ketoacids, whose endogenous concentration is controlled by metabolism, have little role in HO clearance. An increased extracellular concentration of pyruvate, however, does have remarkable peroxide scavenging effects, considering minimal peroxidase activity in this space.
丙酮酸是一种重要的葡萄糖代谢物,是一种与过氧化氢 (HO) 反应的α-酮酸。其药理学前体,乙基丙酮酸,在各种疾病的动物模型中显示出抗炎/抗组织损伤作用,但在多中心临床试验中失败。由于啮齿动物而不是人类可以在血浆中将乙基丙酮酸转化为丙酮酸,因此这种额外的细胞外丙酮酸来源可能导致了物种间的差异。为了检验这种可能性,我们在生物条件下研究了反应的动力学,并确定了第二级反应速率常数 k 为 2.360±0.198 M s。然后我们计算了丙酮酸消除 HO 所需的时间。结果表明,在丙酮酸的平均细胞内浓度(150µM)下,消除正常至病理浓度(0.01-50µM)的 95%HO 需要 141-185 分钟(2.4-3 小时)。对于 1000µM 的丙酮酸,这一浓度只能存在于细胞外或细胞培养基中,消除 5-200µM 的 95%HO 需要 21-25 分钟。我们得出结论,细胞内丙酮酸或其他由代谢控制的α-酮酸,在 HO 清除中作用不大。然而,由于该空间中过氧化物酶活性极小,增加细胞外丙酮酸浓度确实具有显著的过氧化物清除作用。