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牛视紫红质编码基因的分离、序列分析及内含子-外显子排列

Isolation, sequence analysis, and intron-exon arrangement of the gene encoding bovine rhodopsin.

作者信息

Nathans J, Hogness D S

出版信息

Cell. 1983 Oct;34(3):807-14. doi: 10.1016/0092-8674(83)90537-8.

DOI:10.1016/0092-8674(83)90537-8
PMID:6194890
Abstract

We have isolated cDNA clones generated from the mRNA encoding the opsin apoprotein of bovine rhodopsin and used these cDNAs to isolate genomic DNA clones containing the complete opsin gene. Nucleotide sequence analysis of the cloned DNAs has yielded a complete amino acid sequence for bovine rhodopsin and provided an intron-exon map of its gene. The mRNA homologous sequences in the 6.4 kb gene consist of a 96 bp 5' untranslated region, a 1044 bp coding region, and a surprisingly long approximately 1400 bp 3' untranslated region, and are divided into five exons by four introns that interrupt the coding region. Secondary structure analysis predicts that the bovine rhodopsin chain, like that of bacteriorhodopsin, contains seven transmembrane segments. Interestingly, three of the four introns are immediately distal to the codons for three of these segments, and one of these introns marks the boundary between the C-terminal domain and a transmembrane domain.

摘要

我们已经分离出从编码牛视紫红质视蛋白脱辅基蛋白的mRNA产生的cDNA克隆,并使用这些cDNA来分离包含完整视蛋白基因的基因组DNA克隆。对克隆DNA的核苷酸序列分析得出了牛视紫红质的完整氨基酸序列,并提供了其基因的内含子-外显子图谱。在这个6.4kb的基因中,与mRNA同源的序列由一个96bp的5'非翻译区、一个1044bp的编码区和一个长得惊人的约1400bp的3'非翻译区组成,并被四个内含子分成五个外显子,这些内含子中断了编码区。二级结构分析预测,牛视紫红质链与细菌视紫红质一样,包含七个跨膜区段。有趣的是,四个内含子中的三个紧接着这些区段中三个区段的密码子下游,其中一个内含子标志着C末端结构域和一个跨膜结构域之间的边界。

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