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果蝇运动视觉中的 ON 和 OFF 通路。

ON and OFF pathways in Drosophila motion vision.

机构信息

MPI for Neurobiology, Department of Systems and Computational Neurobiology, Am Klopferspitz 18, 82152 Martinsried, Germany.

出版信息

Nature. 2010 Nov 11;468(7321):300-4. doi: 10.1038/nature09545.

Abstract

Motion vision is a major function of all visual systems, yet the underlying neural mechanisms and circuits are still elusive. In the lamina, the first optic neuropile of Drosophila melanogaster, photoreceptor signals split into five parallel pathways, L1-L5. Here we examine how these pathways contribute to visual motion detection by combining genetic block and reconstitution of neural activity in different lamina cell types with whole-cell recordings from downstream motion-sensitive neurons. We find reduced responses to moving gratings if L1 or L2 is blocked; however, reconstitution of photoreceptor input to only L1 or L2 results in wild-type responses. Thus, the first experiment indicates the necessity of both pathways, whereas the second indicates sufficiency of each single pathway. This contradiction can be explained by electrical coupling between L1 and L2, allowing for activation of both pathways even when only one of them receives photoreceptor input. A fundamental difference between the L1 pathway and the L2 pathway is uncovered when blocking L1 or L2 output while presenting moving edges of positive (ON) or negative (OFF) contrast polarity: blocking L1 eliminates the response to moving ON edges, whereas blocking L2 eliminates the response to moving OFF edges. Thus, similar to the segregation of photoreceptor signals in ON and OFF bipolar cell pathways in the vertebrate retina, photoreceptor signals segregate into ON-L1 and OFF-L2 channels in the lamina of Drosophila.

摘要

运动视觉是所有视觉系统的主要功能,但潜在的神经机制和电路仍然难以捉摸。在果蝇的第一视神经节——外节中,光感受器信号分为 L1-L5 五条平行的通路。在这里,我们通过结合遗传阻断和不同外节细胞类型的神经活动重建以及对下游运动敏感神经元的全细胞记录,来研究这些通路如何有助于视觉运动检测。我们发现,如果阻断 L1 或 L2,对运动光栅的反应会减少;然而,仅重建 L1 或 L2 的光感受器输入会导致野生型反应。因此,第一个实验表明这两条通路都是必需的,而第二个实验则表明每条单独的通路都是充分的。这种矛盾可以通过 L1 和 L2 之间的电耦合来解释,即使只有一条通路接收光感受器输入,也可以激活两条通路。当阻断 L1 或 L2 的输出,同时呈现正(ON)或负(OFF)对比度极性的运动边缘时,L1 通路和 L2 通路之间的一个基本区别就显现出来:阻断 L1 会消除对运动 ON 边缘的反应,而阻断 L2 会消除对运动 OFF 边缘的反应。因此,类似于脊椎动物视网膜中光感受器信号在 ON 和 OFF 双极细胞通路中的分离,光感受器信号在外节的 ON-L1 和 OFF-L2 通道中分离。

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