Lee C Y, Schmidt J J, Johnson-Winegar A D, Spero L, Iandolo J J
J Bacteriol. 1987 Sep;169(9):3904-9. doi: 10.1128/jb.169.9.3904-3909.1987.
The DNA encoding the exfoliative toxin A gene (eta) of Staphylococcus aureus was cloned into bacteriophage lambda gt11 and subsequently into plasmid pLI50 on a 1,391-base-pair DNA fragment of the chromosome. Exfoliative toxin A is expressed in the Escherichia coli genetic background, is similar in length to the toxin purified from culture medium, and is biologically active in an animal assay. The nucleotide sequence of the DNA fragment containing the gene was determined. The protein deduced from the nucleotide sequence is a polypeptide of 280 amino acids. The mature protein is 242 amino acids. The DNA sequence of the exfoliative toxin B gene was also determined. Corrections indicate that the amino acid sequence of exfoliative toxin B is in accord with chemical sequence data.
将金黄色葡萄球菌的剥脱毒素A基因（eta）编码的DNA克隆到噬菌体λgt11中，随后又克隆到染色体上一个1391碱基对的DNA片段的质粒pLI50中。剥脱毒素A在大肠杆菌遗传背景中表达，其长度与从培养基中纯化的毒素相似，并且在动物试验中具有生物活性。测定了包含该基因的DNA片段的核苷酸序列。从核苷酸序列推导的蛋白质是一个由280个氨基酸组成的多肽。成熟蛋白为242个氨基酸。还测定了剥脱毒素B基因的DNA序列。校正表明剥脱毒素B的氨基酸序列与化学序列数据一致。
