de Bruijn W C, Den Breejen P
Histochem J. 1976 Mar;8(2):121-42. doi: 10.1007/BF01007164.
By application of appropriate blocking reactions (acetylation, de-amination, methylation and NaHSO3-treatment) it is demonstrated that the tissue ligands involved in the selective glycogen contrast staining reaction with the OsVI. FeII complex (known to be present in the combination K2OsO4K4Fe(CN)6) are the glycogen C2-C3 di-hydroxyl groups. Deliberate conversion of the diols into di-aldehydes and (di-)carboxyl groups by the application of specific oxidative agents followed by application of the OsVI. FeII-complex results morphologically in identical selective contrast staining of glycogen. By applying appropriate blocking reactions to such pre-oxidized aldehyde fixed glycogen, evidence is accumulated that K2OSO4 and K3Fe(CN)6 are unable to oxidize diols, whereas OSO4 and H2O2 are able to convert diols into carboxyl groups. From these results it is concluded that in the combination K2OSO4K4Fe(CN)6 the OsVI.FeII complex reacts with unchanged diols in the glycogen, whereas the OSO4 in the combination OSO4K3Fe(CN)6 can potentially create carbocyl groups in the aldehyde-fixed glycogen. The addition of urea to the two glycogen contrasting combinations (K2OSO4K4Fe(CN)6 or OSO4K3Fe(CN)6), also emphasizes that, although morphologically both combinations produce identical contrast stained glycogen, chemically the contrast staining is apparently obtained in a different way, as urea prevented the contrast formation in the glycogen by the combination K2OsO4Fe(CN)L, but not by the combination OSO4K3F e(CN)6.
通过应用适当的封闭反应(乙酰化、脱氨基、甲基化和亚硫酸氢钠处理),结果表明,与OsVI.FeII络合物(已知存在于K2OsO4·K4Fe(CN)6组合中)发生选择性糖原对比染色反应的组织配体是糖原的C2 - C3二羟基。通过应用特定的氧化剂将二醇故意转化为二醛和(二)羧基,随后应用OsVI.FeII络合物,在形态上导致糖原出现相同的选择性对比染色。通过对这种预氧化醛固定的糖原应用适当的封闭反应,积累的证据表明K2OSO4和K3Fe(CN)6无法氧化二醇,而OSO4和H2O2能够将二醇转化为羧基。从这些结果可以得出结论,在K2OSO4·K4Fe(CN)6组合中,OsVI.FeII络合物与糖原中未改变的二醇反应,而在OSO4·K3Fe(CN)6组合中的OSO4可能在醛固定的糖原中产生羧基。向两种糖原对比组合(K2OSO4·K4Fe(CN)6或OSO4·K3Fe(CN)6)中添加尿素,也强调了尽管在形态上两种组合都产生相同的对比染色糖原,但在化学上对比染色显然是以不同的方式获得的,因为尿素阻止了K2OsO4·Fe(CN)L组合在糖原中形成对比,但没有阻止OSO4·K3Fe(CN)6组合。