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酿酒酵母中特定组蛋白基因的转录需要SPT10和SPT21。

SPT10 and SPT21 are required for transcription of particular histone genes in Saccharomyces cerevisiae.

作者信息

Dollard C, Ricupero-Hovasse S L, Natsoulis G, Boeke J D, Winston F

机构信息

Department of Genetics, Harvard Medical School, Boston, Massachusetts 02115.

出版信息

Mol Cell Biol. 1994 Aug;14(8):5223-8. doi: 10.1128/mcb.14.8.5223-5228.1994.

Abstract

The Saccharomyces cerevisiae genome contains four loci that encode histone proteins. Two of these loci, HTA1-HTB1 and HTA2-HTB2, each encode histones H2A and H2B. The other two loci, HHT1-HHF1 and HHT2-HHF2, each encode histones H3 and H4. Because of their redundancy, deletion of any one histone locus does not cause lethality. Previous experiments demonstrated that mutations at one histone locus, HTA1-HTB1, do cause lethality when in conjunction with mutations in the SPT10 gene. SPT10 has been shown to be required for normal levels of transcription of several genes in S. cerevisiae. Motivated by this double-mutant lethality, we have now investigated the interactions of mutations in SPT10 and in a functionally related gene, SPT21, with mutations at each of the four histone loci. These experiments have demonstrated that both SPT10 and SPT21 are required for transcription at two particular histone loci, HTA2-HTB2 and HHF2-HHT2, but not at the other two histone loci. These results suggest that under some conditions, S. cerevisiae may control the level of histone proteins by differential expression of its histone genes.

摘要

酿酒酵母基因组包含四个编码组蛋白的基因座。其中两个基因座,HTA1-HTB1和HTA2-HTB2,各自编码组蛋白H2A和H2B。另外两个基因座,HHT1-HHF1和HHT2-HHF2,各自编码组蛋白H3和H4。由于它们的冗余性,删除任何一个组蛋白基因座都不会导致致死性。先前的实验表明,当与SPT10基因中的突变一起出现时,一个组蛋白基因座HTA1-HTB1处的突变确实会导致致死性。已证明SPT10是酿酒酵母中几个基因正常转录水平所必需的。受这种双突变致死性的启发,我们现在研究了SPT10和功能相关基因SPT21中的突变与四个组蛋白基因座中每个基因座处的突变之间的相互作用。这些实验表明,SPT10和SPT21都是两个特定组蛋白基因座HTA2-HTB2和HHF2-HHT2转录所必需的,但不是另外两个组蛋白基因座转录所必需的。这些结果表明,在某些条件下,酿酒酵母可能通过其组蛋白基因的差异表达来控制组蛋白的水平。

https://cdn.ncbi.nlm.nih.gov/pmc/blobs/ff2c/359041/20dbd64cff5b/molcellb00008-0217-a.jpg

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